将列表值与字典匹配，并在新字典中返回键/值对

问题描述

我有一个代表字典值的列表.我试图解析字典以查找也在列表中的值，然后从中创建一个仅包含匹配值的新字典:

I have a list that represents the values of a dictionary. I am trying to parse the dictionary looking for values that are also in my list and creating a new dictionary from this that contains only the matched values:

a = [1, 2, 3]
b = {"aye":1, "bee":2, "cee":3, "dee":4, "eee":5}

new_dict = dict((k, v) for k, v in b.iteritems() if k in a)
print new_dict

我想要的输出应如下所示:

My desired output should look like this:

new_dict = {"aye":1, "bee":2, "cee":3}

但是，我回来的只是:

{}

谁能告诉我我要去哪里错了?

Can anyone tell me where I am going wrong?

推荐答案

k表示键，而v值

>>> a = [1, 2, 3]
>>> b = {"aye":1, "bee":2, "cee":3, "dee":4, "eee":5}
>>> new_dict = dict((k, v) for k, v in b.iteritems() if v in a)
>>> print new_dict
{'aye': 1, 'cee': 3, 'bee': 2}

因此，要实现您想要的目标，您必须执行if v in a.

So therefore to achieve what you want, you have to do if v in a instead.

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