动态地将链接添加到datagridview

本文介绍了动态地将链接添加到datagridview的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！

问题描述

我已填充7列的datagridview.现在我想向1列(即数字)添加链接.单击此链接后，它将显示基于该数字的详细信息.

I have my datagridview filled which have 7 columns.Now I want to add link to 1 column(i.e Number).After clicking this link,it will display details based on that number.
Please can any1 help me out?

推荐答案

Dim lnk As New DataGridViewLinkColumn()
       DataGridView1.Columns.Add(lnk)
       lnk.HeaderText = "Link Data"
       lnk.Name = "Link"
       lnk.Text = "Link"
       lnk.UseColumnTextForLinkValue = True

并使用DataKeyNames(PrimaryKey索引)和列的值来获取数据以显示结果.

http://msdn.microsoft.com/en-us/library/system. windows.forms.datagridviewlinkcolumn.aspx [ ^ ]

And Use the DataKeyNames(PrimaryKey index) and the value of the column to get the data to display the results.

http://msdn.microsoft.com/en-us/library/system.windows.forms.datagridviewlinkcolumn.aspx[^]

<asp:GridView ID="GridView1" runat="server" EnableViewState="false" AutoGenerateColumns="False"

    ShowFooter="True" DataKeyNames="VendorId" AllowPaging="True" CellPadding="3"

    PageSize="5" BackColor="White" BorderColor="White" BorderStyle="Ridge" CellSpacing="1"

    Width="100%" BorderWidth="2px" GridLines="None" AllowSorting="true"  OnRowDataBound="gv_RowDataBound">
    <Columns>
        <asp:TemplateField HeaderText="Edit" ShowHeader="False">
            <ItemTemplate>
                <asp:LinkButton ID="complain_no" runat="server" CausesValidation="False" CommandName="complain_no"

                    Text="complain_no"></asp:LinkButton>
            </ItemTemplate>
        </asp:TemplateField>
        <asp:TemplateField HeaderText="date" SortExpression="VendorFName">

            <ItemTemplate>
                <asp:Label ID="Label1" runat="server" Text='<%# Bind("date") %>'></asp:Label>
            </ItemTemplate>
        </asp:TemplateField>
        <asp:TemplateField HeaderText="name" SortExpression="VendorLName">
            <ItemTemplate>
                <asp:Label ID="name" runat="server" Text='<%# Bind("name") %>'></asp:Label>
            </ItemTemplate>
        </asp:TemplateField>

    </Columns>
    <RowStyle BackColor="#DEDFDE" ForeColor="Black" />
    <FooterStyle BackColor="#C6C3C6" ForeColor="Black" />
    <PagerStyle ForeColor="Black" HorizontalAlign="Right" BackColor="#C6C3C6" />
    <SelectedRowStyle BackColor="#9471DE" Font-Bold="True" ForeColor="White" />
    <HeaderStyle BackColor="#4A3C8C" Font-Bold="True" ForeColor="#E7E7FF" />
</asp:GridView>



protected void gv_RowDataBound(object sender, GridViewRowEventArgs e)
    {
       // Use debug and see the column which u got.
       // check the column. if its linkbutton column then
       // do your code here.

    }

}

private void DgvView_CellClick(object sender, DataGridViewCellEventArgs e)
        {
            try
            {
                if (e.ColumnIndex == 0)//if ur link columnIndex (complain_no ColumnIndex) is zero 
                {
                  // Display your data here
                }
            }
            catch(Exception e)
            {
            }
         }

//在vb.net中也执行相同的步骤.因此请转换为vb.net代码.

// same procedure in vb.net also. so convert into vb.net code.

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