在 Access 中计算 SQL 中数据分布的偏度，无需额外的子查询

问题描述

我在 Access 数据库中有一个数据集，为简单起见，如下所示:

ID 组员工票 ID------ --------- -------- -----------------1 阿乔 1234142 阿乔 123091243 鲍勃 1123213214 鲍勃 2131232141425 山姆 1232142141246 B 仁 4129492184197 B 艾米 12341234213

我想要做的是计算分布的统计偏度每个员工都处理过的票.

在一个完美的世界中，我的 SQL 应该是这样的:

SELECT[组], SKEW([myCount]) AS mySkew从(SELECT [Group], [Employee], COUNT(*) AS myCount从我的表GROUP BY [组], [员工])临时表通过...分组[团体];

但是，Access 似乎没有 SKEW 功能.有谁知道我怎么做这个计算?

解决方案

看起来有人已经尝试过并为此创建了一个小型库:

http://www.experts-exchange.com/Microsoft/Development/MS_Access/A_2529-Median-Mode-Skewness-and-Kurtosis-in-MS-Access.html

I have a dataset in an Access database that, for simplicity's sake, looks like this:

      ID     Group   Employee       Ticket ID
    ------ --------- -------- -----------------
      1        A       Joe           123414
      2        A       Joe           12309124
      3        A       Bob           112321321
      4        A       Bob           213123214142
      5        A       Sam           123214214124
      6        B       Jen           412949218419
      7        B       Amy           12341234213

What I'm trying to do is calculate the statistical skewness of distribution of the number of tickets each employee has handled.

In a perfect world, my SQL would be this:

SELECT
    [Group], SKEW([myCount]) AS mySkew
FROM
    (
     SELECT [Group], [Employee], COUNT(*) AS myCount
     FROM MyTable
     GROUP BY [Group], [Employee]
    )
        AS TempTable
GROUP BY
   [Group];

However, it appears that Access does not have a SKEW function. Anyone know how I can do this calculation?

解决方案

It looks like somebody has tried this and created a small library for it here:

http://www.experts-exchange.com/Microsoft/Development/MS_Access/A_2529-Median-Mode-Skewness-and-Kurtosis-in-MS-Access.html

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