本文介绍了将文件上传到Web服务器的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述



我在vb.net中有一个窗口应用程序.我需要通过窗口应用程序(桌面)将一些文件上传到Web服务器(例如http:/www.domain.com/directory).

我是vb.net的新手.所以请帮我解决我的问题.

谢谢

Hi,

I have a window application in vb.net. I need to upload some file to webserver (e.g. http:/www.domain.com/directory) form my window application (desktop).

I am new in vb.net. so please help me regarding my problem.

Thanks

推荐答案


public static  void UploadFilesToRemoteUrl(string url, string[] files, string logpath, NameValueCollection nvc)
{
    long length = 0;
    string boundary = "----------------------------" + DateTime.Now.Ticks.ToString("x");
    HttpWebRequest httpWebRequest2 = (HttpWebRequest)WebRequest.Create(url);
    httpWebRequest2.ContentType = "multipart/form-data; boundary=" + boundary;
    httpWebRequest2.Method      = "POST";
    httpWebRequest2.KeepAlive   = true;
    httpWebRequest2.Credentials = System.Net.CredentialCache.DefaultCredentials;

    Stream memStream = new System.IO.MemoryStream();
    byte[] boundarybytes = System.Text.Encoding.ASCII.GetBytes("\r\n--" + boundary + "\r\n");
    string formdataTemplate = "\r\n--" + boundary + "\r\nContent-Disposition: form-data; name=\"{0}\";\r\n\r\n{1}";
    foreach (string key in nvc.Keys)
    {
        string formitem = string.Format(formdataTemplate, key, nvc[key]);
        byte[] formitembytes = System.Text.Encoding.UTF8.GetBytes(formitem);
        memStream.Write(formitembytes, 0, formitembytes.Length);
    }
    memStream.Write(boundarybytes, 0, boundarybytes.Length);
    string headerTemplate = "Content-Disposition: form-data; name=\"{0}\"; filename=\"{1}\"\r\n Content-Type: application/octet-stream\r\n\r\n";
    for (int i = 0; i < files.Length; i++)
    {
        //string header = string.Format(headerTemplate, "file" + i, files[i]);  
        string header = string.Format(headerTemplate, "uplTheFile", files[i]);
        byte[] headerbytes = System.Text.Encoding.UTF8.GetBytes(header);
        memStream.Write(headerbytes, 0, headerbytes.Length);
        FileStream fileStream = new FileStream(files[i], FileMode.Open, FileAccess.Read);
        byte[] buffer = new byte[1024];
        int bytesRead = 0;
        while ((bytesRead = fileStream.Read(buffer, 0, buffer.Length)) != 0)
        {
            memStream.Write(buffer, 0, bytesRead);
        }
        memStream.Write(boundarybytes, 0, boundarybytes.Length);
        fileStream.Close();
    }
    httpWebRequest2.ContentLength = memStream.Length;
    Stream requestStream = httpWebRequest2.GetRequestStream();
    memStream.Position = 0;
    byte[] tempBuffer = new byte[memStream.Length];
    memStream.Read(tempBuffer, 0, tempBuffer.Length);
    memStream.Close();
    requestStream.Write(tempBuffer, 0, tempBuffer.Length);
    requestStream.Close();
    WebResponse webResponse2 = httpWebRequest2.GetResponse();
    Stream stream2 = webResponse2.GetResponseStream();
    StreamReader reader2 = new StreamReader(stream2);
    MessageBox.Show(reader2.ReadToEnd());
    webResponse2.Close();
    httpWebRequest2 = null;
    webResponse2 = null;
}



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08-03 21:08
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