问题描述
我想根据返回的不同model_names(类)对结果进行分析.有没有简单的方法可以做到这一点?
I want to facet the results based on the different model_names (classes) returned. Is there an easy way to do this?
推荐答案
您是否尝试添加带有此信息的SearchIndex
字段?例如
Have you tried adding a SearchIndex
field with this information? E.g.
class NoteIndex(SearchIndex, indexes.Indexable):
title = CharField(model_attr='title')
facet_model_name = CharField(faceted=True)
def get_model(self):
return Note
def prepare_facet_model_name(self, obj):
return "note"
class MemoIndex(SearchIndex, indexes.Indexable):
title = CharField(model_attr='title')
facet_model_name = CharField(faceted=True)
def get_model(self):
return Memo
def prepare_facet_model_name(self, obj):
return "memo"
依此类推,只需为每个搜索索引返回不同的字符串即可.您也可以创建一个mixin并返回get_model
返回的模型的名称.
And so on, simply returning a different string for each search index. You could also create a mixin and return the name of the model returned by get_model
too.
假设您已将此字段添加到每个SearchIndex
定义中,只需将facet
方法链接到您的结果.
Presuming you've added this field to each of your SearchIndex
definitions, just chain the facet
method to your results.
results = form.search().facet('facet_model_name')
现在facet_counts
方法将返回一个包含多面字段的字典,并为每个小面值(在本例中为模型名称)计算结果.
Now the facet_counts
method will return a dictionary with the faceted fields and count of results for each facet value, in this case, the model names.
请注意,此处的字段被详细标记,以免与Haystack添加的字段model_name
发生冲突.它不是多面的,我不确定复制它是否会引起冲突.
Note that the field here is labeled verbosely to avoid a possible conflict with model_name
, a field added by Haystack. It's not faceted, and I'm not sure if duplicating it will cause a conflict.
这篇关于模型类型上的Django Haystack构面的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!