问题描述
这是我的 cron 工作:
Here is my cron job:
plee@dragon:~$ crontab -l
* * * * * /bin/bash -l -c 'source ~/.bashrc; echo $EDITOR > /tmp/cronjob.test'
在 ~/.bashrc
文件中,我有 export EDITOR=vim
,但在最终的 /tmp/cronjob.test 文件中,还是空的?
and inside ~/.bashrc
file, I have export EDITOR=vim
, but in the final /tmp/cronjob.test
file, it's still empty?
那么如何获取环境变量(在 .bashrc
文件中设置)并在我的 cron 作业中使用它?
So how can I get the environment variables (set in .bashrc
file) and use it in my cron job?
plee@dragon:~$ lsb_release -a
No LSB modules are available.
Distributor ID: Ubuntu
Description: Ubuntu 12.04 LTS
Release: 12.04
Codename: precise
plee@dragon:~$ uname -a
Linux dragon 3.2.0-26-generic-pae #41-Ubuntu SMP Thu Jun 14 16:45:14 UTC 2012 i686 i686 i386 GNU/Linux
如果使用这个:
* * * * * /bin/bash -l -c -x 'source ~/.bashrc; echo $EDITOR > /tmp/cronjob.test' 2> /tmp/cron.debug.res
在/tmp/cron.debug.res
:
...
++ return 0
+ source /home/plee/.bashrc
++ '[' -z '' ']'
++ return
+ echo
顺便说一句,.bashrc
文件是 Ubuntu 12.04 附带的默认文件,除了我添加了一行 export EDITOR=vim
.
BTW, the .bashrc
file is the default one came with Ubuntu 12.04, with the exception that I added one line export EDITOR=vim
.
如果我不使用 cron 作业,则直接在命令行上执行此操作:
If I don't use the cron job, instead, just directly do this on the command line:
source .bashrc; echo $EDITOR # Output: vim
推荐答案
source ~/.bashrc
不工作的原因是你的~/.bashrc
上的内容(默认来自 Ubuntu 12.04).如果您查看它,您将在第 5 行和第 6 行看到以下内容:
The reason for source ~/.bashrc
not working is the contents on your ~/.bashrc
(default one from Ubuntu 12.04). If you look in it you will see on lines 5 and 6 the following:
# If not running interactively, don't do anything
[ -z "$PS1" ] && return
PS1
变量是为交互式 shell 设置的,因此在通过 cron
运行时它不存在,即使您将其作为登录 shell 执行也是如此.这由 /bin/bash -l -c -x 'source ~/.bashrc; 生成的文件的内容确认.回声 $EDITOR >/tmp/cronjob.test'
:
PS1
variable is set for an interactive shell, so it's absent when run via cron
, even though you are executing it as a login shell. This is confirmed by contents of the file produced by /bin/bash -l -c -x 'source ~/.bashrc; echo $EDITOR > /tmp/cronjob.test'
:
+ source /home/plee/.bashrc
++ '[' -z '' ']'
++ return
要使 source ~/.bashrc
工作,请注释掉检查 ~/.bashrc
中是否存在 PS1
变量的行:
To make source ~/.bashrc
work, comment out the line that checks for presence of the PS1
variable in ~/.bashrc
:
#[ -z "$PS1" ] && return
这将使 bash
通过 cron
这篇关于Cron 作业没有获得在 .bashrc 中设置的环境变量的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!