本文介绍了从网址保存XML并阅读的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我正在制作android应用,我需要从URL
下载一个xml
文件并打开它,我该怎么做?
I'm making android App and I need to download a xml
file from an URL
and open it,How I can do this?
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
File dir1 = getDir("xmls",Context.MODE_PRIVATE);//Creating an internal dir;
System.out.println("dir1: " + dir1);
//Saving The File
try {
URL url = new URL("http://www. the url of my xml .xml");
// The server thinks this request is from an Opera browser!
String userAgent = "Opera/9.63 (Windows NT 5.1; U; en) Presto/2.1.1";
System.out.println("Downloading ...");
downloadFromUrl(url, dir1+"news.xml", userAgent);
System.out.println("OK");
} catch (Exception e) {
System.err.println(e);
System.out.println("Entri pure nel catch");
}
//This is the path of the xml file that i have saved
URL = dir1+"/news.xml" ;
ArrayList<HashMap<String, String>> songsList =
new ArrayList<HashMap<String, String>>();
XMLParser parser = new XMLParser();
String xml = parser.getXmlFromUrl(URL); // getting XML from UR
Document doc = parser.getDomElement(xml); // getting DOM element
//And then i do all the parsing
NodeList nl = doc.getElementsByTagName(KEY_CATEGORIA);
XMlParser
类是这样的:
public class XMLParser_Categorie {
// constructor
public XMLParser_Categorie() {
}
/**
* Getting XML from URL making HTTP request
* @param url string
* */
public String getXmlFromUrl(String url) {
String xml = null;
try {
// defaultHttpClient
DefaultHttpClient httpClient = new DefaultHttpClient();
HttpPost httpPost = new HttpPost(url);
HttpResponse httpResponse = httpClient.execute(httpPost);
HttpEntity httpEntity = httpResponse.getEntity();
xml = EntityUtils.toString(httpEntity);
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
} catch (ClientProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
// return XML
return xml;
}
我需要更改此说明:
DefaultHttpClient httpClient = new DefaultHttpClient();
HttpPost httpPost = new HttpPost(url);
HttpResponse httpResponse = httpClient.execute(httpPost);
HttpEntity httpEntity = httpResponse.getEntity();
xml = EntityUtils.toString(httpEntity);
这是来自本地目录的请求,而不是来自http的请求.
It a request from a local directory and non an http request.
推荐答案
以下是适合您的代码段,
Here is code snippet for you ,
try {
URL url = new URL("your url goes here");
//create the new connection
HttpURLConnection urlConnection = (HttpURLConnection) url.openConnection();
urlConnection.connect();
//set the path where we want to save the file
//in this case, going to save it on the root directory of the
//sd card.
File SDCardRoot = Environment.getExternalStorageDirectory();
//create a new file, specifying the path, and the filename
//which we want to save the file as.
File file = new File(SDCardRoot,"Demo.xml");
//this will be used to write the downloaded data into the file we created
FileOutputStream fileOutput = new FileOutputStream(file);
//this will be used in reading the data from the internet
InputStream inputStream = urlConnection.getInputStream();
//this is the total size of the file
int totalSize = urlConnection.getContentLength();
progressDialog.setMax(totalSize);
//variable to store total downloaded bytes
int downloadedSize = 0;
//create a buffer...
byte[] buffer = new byte[1024];
int bufferLength = 0; //used to store a temporary size of the buffer
//now, read through the input buffer and write the contents to the file
while ( (bufferLength = inputStream.read(buffer)) > 0 ) {
//add the data in the buffer to the file in the file output stream (the file on the sd card
fileOutput.write(buffer, 0, bufferLength);
//add up the size so we know how much is downloaded
downloadedSize += bufferLength;
}
//close the output stream when done
fileOutput.close();
//catch some possible errors...
} catch (MalformedURLException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
否则这些链接可以为您提供帮助,
Else these link can help you,
这篇关于从网址保存XML并阅读的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!