问题描述
我需要一种方法来上传文件并将其发布到php页面...
I need a way to upload a file and POST it into php page...
我的php页面是:
<?php
$maxsize = 10485760;
$array_estensioni_ammesse=array('.tmp');
$uploaddir = 'uploads/';
if (is_uploaded_file($_FILES['file']['tmp_name']))
{
if($_FILES['file']['size'] <= $maxsize)
{
$estensione = strtolower(substr($_FILES['file']['name'], strrpos($_FILES['file']['name'], "."), strlen($_FILES['file']['name'])-strrpos($_FILES['file']['name'], ".")));
if(!in_array($estensione, $array_estensioni_ammesse))
{
echo "File is not valid!\n";
}
else
{
$uploadfile = $uploaddir . basename($_FILES['file']['name']);
echo "File ". $_FILES['file']['name'] ." uploaded successfully.\n";
if (move_uploaded_file($_FILES['file']['tmp_name'], $uploadfile))
{
echo "File is valid, and was successfully moved.\n";
}
else
print_r($_FILES);
}
}
else
echo "File is not valid!\n";
}
else
{
echo "Upload Failed!!!";
print_r($_FILES);
}
?>
我在桌面应用程序中使用这个java代码:
and i use this java code in my desktop application:
HttpURLConnection httpUrlConnection = (HttpURLConnection)new URL("http://www.mypage.org/upload.php").openConnection();
httpUrlConnection.setDoOutput(true);
httpUrlConnection.setRequestMethod("POST");
OutputStream os = httpUrlConnection.getOutputStream();
Thread.sleep(1000);
BufferedInputStream fis = new BufferedInputStream(new FileInputStream("tmpfile.tmp"));
for (int i = 0; i < totalByte; i++) {
os.write(fis.read());
byteTrasferred = i + 1;
}
os.close();
BufferedReader in = new BufferedReader(
new InputStreamReader(
httpUrlConnection.getInputStream()));
String s = null;
while ((s = in.readLine()) != null) {
System.out.println(s);
}
in.close();
fis.close();
但我总是收到上传失败!!!消息。
But I receive always the "Upload Failed!!!" message.
推荐答案
即使线程很老,仍然可能有人在寻找更简单的方法来解决这个问题问题(像我一样:))
Even though the thread is very old, there may still be someone around looking for a more easy way to solve this problem (like me :))
经过一番研究后,我发现了一种在不改变原版海报的Java代码的情况下上传文件的方法。
您只需使用以下PHP代码:
After some research I found a way to uplaod a file without changing the original poster's Java-Code.You just have to use the following PHP-code:
<?php
$filename="abc.xyz";
$fileData=file_get_contents('php://input');
$fhandle=fopen($filename, 'wb');
fwrite($fhandle, $fileData);
fclose($fhandle);
echo("Done uploading");
?>
此代码只是获取java应用程序发送的原始数据并将其写入文件。
然而有一个问题:你没有得到原始文件名,所以你必须以其他方式传输它。
This code is just fetching the raw data sent by the java-application and writing it into a file.There is, however one problem: You dont get the original filename, so you have to transmit it somehow else.
我通过使用GET参数解决了这个问题,它对必要的Java代码进行了一些改动:
I solved this problem by using a GET-Parameter, which makes a little change in the Java-code necessary:
HttpURLConnection httpUrlConnection = (HttpURLConnection)new URL("http://www.mypage.org/upload.php").openConnection();
更改为
HttpURLConnection httpUrlConnection = (HttpURLConnection)new URL("http://www.mypage.org/upload.php?filename=abc.def").openConnection();
在PHP脚本中更改行
$filename="abc.xyz";
到
$filename=$_GET['filename'];
此解决方案不使用任何外部库,在我看来比其他一些更简单张贴的......
This solution doesn't use any external librarys and seems to me much more simple than some of the other posted ones...
希望我可以帮助任何人:)
Hope I could help anyone:)
这篇关于使用Java将文件上载和POST文件到PHP页面的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!