调试器将我的某些命令视为未声明的变量

本文介绍了调试器将我的某些命令视为未声明的变量的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！

问题描述

这是我遇到问题的代码.当我进入命令cout和cin时，就会出现问题，其中调试器(和编译器，即GNU)将命令视为未声明的变量.请告诉我问题和解决方法.谢谢.

here is the code where im having the problem. the problem arises when i get to the commands cout and cin, where the debugger (and compiler, which is GNU) see the commands as undeclared variables. Please tell me the problem and solution. thanks.

#include (cstdio)
#include (cstdlib)
#include (iostream)
using namespace std;

int main(int nNumberofArgs, char* pszArgs[])
{
     int nNumber;
     int nNumber2;

     cout << "numero uno - " << endl;
     cin >> nNumber;

     cout << "nombre du - " << endl;
     cin >> nNumber2;

     cout << "the equation = \n" << endl;
     cout << (nNumber - nNumber2 * nNumber) + 5;
     cout << "\n" << endl;
     system("PAUSE");
     return 0;

}

[edit]已添加代码块-OriginalGriff [/edit]

[edit]Code block added - OriginalGriff[/edit]

推荐答案

#include <iostream>
//..

#include <cstdio.h>

或

#include "cstdio.h"

不知道将其放在括号中会发生什么. cout和cin应该在iostream中定义.h

Not sure what happens when you put it in parenthesis. cout and cin should be defined in iostream.h

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Problem