问题描述
我只是尝试MonodroidApp(AndroidEmulator)和localDevServer之间发送和接收数据。我明白本地主机是专门映射为10.0.2.2的AndroidEmulator,所以我做了以下,但应用程序没有响应。
I simply try to send and receive data between MonodroidApp(AndroidEmulator) and a localDevServer. I understand localhost is specially mapped to "10.0.2.2" on AndroidEmulator, so I did the following, but the app does not respond.
System.Text.Encoding enc = System.Text.Encoding.UTF8;
string sendMsg = "testtest";
byte[] sendBytes = enc.GetBytes(sendMsg);
int localPort = 39000;
var udp = new System.Net.Sockets.UdpClient(localPort);
//send data
string remoteHost = "10.0.2.2";//"127.0.0.1";
int remotePort = 15000;
udp.Send(sendBytes, sendBytes.Length,
remoteHost, remotePort);
//receive data
System.Net.IPEndPoint remoteEP = null;
byte[] rcvBytes = udp.Receive(ref remoteEP);
string rcvMsg = enc.GetString(rcvBytes);
Console.WriteLine("received data:{0}", rcvMsg);
Console.WriteLine("sender address:{0}/port:{1}",
remoteEP.Address, remoteEP.Port);
这code被证实与单声道工作的Mac和使用指针localDevServer:远程主机=127.0.0.1
This code is verified to work with Mono for Mac and the localDevServer with the pointer: remoteHost = "127.0.0.1"
所以,
REMOTEHOST =10.0.2.2的模式是行不通的。
remoteHost = "10.0.2.2" pattern does not work.
我怎么会错过?任何人,任何想法?
What do I miss? Anyone, any thought?
感谢你。
推荐答案
好,一个重要的事情,我忘了提的是我使用的为Android模拟器是Genymotion。
Ok, one important thing I forgot to mention isThe emulator I use for android is Genymotion.
因此,这似乎是,10.0.2.2并不本地主机指向默认
So, it appears to be that "10.0.2.2" does not point localhost as default.
http://blog.zeezonline.com/2013/11/access-localhost-from-genymotion/
在我的环境中(OSX 10.9)与Genymotion,从仿真器的本地主机地址
In my environment(OSX 10.9) with Genymotion,the localhost address from the emulator is
10.0.3.2 ,和code ++工程。
"10.0.3.2", and the code works.
这篇关于UDP从AndroidEmulator(--Genymotion--)到本地主机服务器(10.0.2.2)不工作?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!