emacs ff-find-other-file找不到我的标题

问题描述

不知怎的，我无法使emacs' ff-find-other-file 来获取我的头文件。这是我有的（最小例子）：

  cd〜/ tmp 
 mkdir test 
 cd test 
 mkdir -p src / a / b inc / a / b 
 echoaaaa> src / a / b / a.cpp 
 echobbbb> inc / a / b / a.hpp 
 tree 
  

给出：

 。 
├──inc 
│└──a 
│└──b 
│└──a.hpp 
└──src 
└ ──a 
└──b 
└──a.cpp 
  

这与我的项目结构类似。

---

  emacs -Q src / a / b / a.cpp 
  

然后在 * scratch * 并执行它与 Cx Ce ：

 （setq cc-search-directories'（。../inc../inc/*../../inc/*../../../inc/* / usr / include））
  

并运行 ff-find-other-文件在缓冲区 a.cpp 中，仅在minibuffer中提示：

请注意，如果从 ff-search-directories 的帮助中引用该引号，而我修改的列表是 cc-search-directories 。我不明白为什么这会有所作为。

这个和其他线程使我相信 * 将递归搜索目录树。错误？

解决方案

* 表示其父级的每个直接子目录;

评论的措辞稍微更清楚：

ie对于这个具体的例子，我会期望../../../ inc / * / b工作。或者确实../../../ inc / * / *（正如你最终使用的那样）。

另请参阅，并特别注意到您可以定义函数来动态生成目标文件路径。

我怀疑你想要 a / b 根据原始路径确定，所以返回相应路径到另一个文件的功能将是您最好的解决方案。

Somehow I can't make emacs' ff-find-other-file to get my header file. Here is what I have (minimal example):

cd ~/tmp
mkdir test
cd test
mkdir -p src/a/b inc/a/b
echo "aaaa" > src/a/b/a.cpp
echo "bbbb" > inc/a/b/a.hpp
tree

gives:

.
├── inc
│   └── a
│       └── b
│           └── a.hpp
└── src
    └── a
        └── b
            └── a.cpp

This is similar to my project structure.

---

emacs -Q src/a/b/a.cpp

Then copying this in *scratch* and executing it with C-x C-e:

(setq cc-search-directories '("." "../inc" "../inc/*" "../../inc/*" "../../../inc/*" "/usr/include"))

and running ff-find-other-file in buffer a.cpp, only results in a prompt in the minibuffer:

C-h v on ff-search-directories returns cc-search-directories, and on cc-search-directories I get the list above.

I expect ff-find-other-file to look in ../../../inc/*, and find a.hpp. Why doesn't it?

---

Edit: it seems to be the recursive part that doesn't work here.

After:

cp inc/a/b/a.hpp inc/

a.hpp is found from a.cpp.

The help about ff-search-directories says:

Note that this quote if from the help for ff-search-directories, while the list I modified is cc-search-directories. I can't see why that would make a difference though.

This and other threads on SO made me believe * would recursively search the directory tree. Wrong?

解决方案

* represents every immediate sub-directory of its parent; nothing more.

The commentary has it worded slightly more clearly:

i.e. For this specific example I would expect "../../../inc/*/b" to work. Or indeed "../../../inc/*/*" (as you've ended up using).

See also https://stackoverflow.com/a/23662870/324105 and note in particular that you can define functions to dynamically generate the target file path(s).

I suspect you want the a/b to be determined based on the original path, so a function to return the appropriate path to the other file would be your best solution here.

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