问题描述
我是 Python 新手,熟悉 Multimaps 在 语言.Python 是否内置了这样的数据结构,或者在常用库中可用?
为了说明我所说的multimap"是什么意思:
a = multidict()a[1] = 'a'a[1] = 'b'[2] = 'c'打印(a[1]) # 打印:['a', 'b']打印(a[2]) # 打印:['c']
这样的东西在标准库中是不存在的.您可以使用 defaultdict
:
(您可能希望使用 set
而不是 list
,在这种情况下,您将调用 .add
而不是 .追加
.)
顺便说一句:看看你写的这两行:
a[1] = 'a'a[1] = 'b'
这似乎表明您希望表达式 a[1]
等于两个不同的值.这对于字典是不可能的,因为它们的键是唯一的,并且每个键都与一个值相关联.但是,您可以做的是,将列表中与给定键关联的所有值一一提取.您可以使用 iter
后跟连续调用next
.或者你可以只使用两个循环:
I am new to Python, and I am familiar with implementations of Multimaps in other languages. Does Python have such a data structure built-in, or available in a commonly-used library?
To illustrate what I mean by "multimap":
a = multidict()
a[1] = 'a'
a[1] = 'b'
a[2] = 'c'
print(a[1]) # prints: ['a', 'b']
print(a[2]) # prints: ['c']
Such a thing is not present in the standard library. You can use a defaultdict
though:
>>> from collections import defaultdict
>>> md = defaultdict(list)
>>> md[1].append('a')
>>> md[1].append('b')
>>> md[2].append('c')
>>> md[1]
['a', 'b']
>>> md[2]
['c']
(Instead of list
you may want to use set
, in which case you'd call .add
instead of .append
.)
As an aside: look at these two lines you wrote:
a[1] = 'a'
a[1] = 'b'
This seems to indicate that you want the expression a[1]
to be equal to two distinct values. This is not possible with dictionaries because their keys are unique and each of them is associated with a single value. What you can do, however, is extract all values inside the list associated with a given key, one by one. You can use iter
followed by successive calls to next
for that. Or you can just use two loops:
>>> for k, v in md.items():
... for w in v:
... print("md[%d] = '%s'" % (k, w))
...
md[1] = 'a'
md[1] = 'b'
md[2] = 'c'
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