文本在指定的长度后分割，但不要使用grails破坏单词

问题描述

我有一个长字符串，需要将其解析为长度不超过50个字符的字符串数组.对于我来说，棘手的部分是确保正则表达式在50个字符之前找到最后一个空格，以使字符串之间清晰地分开，因为我不想切断单词.

I have a long string that I need to parse into an array of strings that do not exceed 50 characters in length. The tricky part of this for me is making sure that the regex finds the last whitespace before 50 characters to make a clean break between strings since I don't want words cut off.

public List<String> splitInfoText(String msg) { 
     int MAX_WIDTH = 50; 
     def line = [] String[] words; 
     msg = msg.trim(); 
     words = msg.split(" "); 
     StringBuffer s = new StringBuffer(); 
     words.each {
        word -> s.append(word + " "); 
        if (s.length() > MAX_WIDTH) { 
          s.replace(s.length() - word.length()-1, s.length(), " "); 
          line << s.toString().trim();
          s = new StringBuffer(word + " "); 
        } 
     } 
     if (s.length() > 0) 
        line << s.toString().trim();
     return line; 
}

推荐答案

尝试一下:

List<String> matchList = new ArrayList<String>();
Pattern regex = Pattern.compile(".{1,50}(?:\\s|$)", Pattern.DOTALL);
Matcher regexMatcher = regex.matcher(subjectString);
while (regexMatcher.find()) {
    matchList.add(regexMatcher.group());
}

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