问题描述
假设我有list_of_numbers = [[1, 2], [3], []]，我想要简单得多的对象列表对象x = [1, 2, 3].
Suppose I have list_of_numbers = [[1, 2], [3], []] and I want the much simpler object list object x = [1, 2, 3].
按照此相关解决方案的逻辑，我愿意
list_of_numbers = [[1, 2], [3], []]
import itertools
chain = itertools.chain(*list_of_numbers)
不幸的是，chain并不是我想要的，因为(例如)在控制台上运行chain会返回<itertools.chain object at 0x7fb535e17790>.
Unfortunately, chain is not exactly what I want because (for instance) running chain at the console returns <itertools.chain object at 0x7fb535e17790>.
函数f是什么，如果我执行x = f(chain)然后在控制台上键入x，我会得到[1, 2, 3]?
What is the function f such that if I do x = f(chain) and then type x at the console I get [1, 2, 3]?
更新:实际上，我最终需要的结果是array([1, 2, 3]).我正在对所选答案的评论中添加一行以解决此问题.
Update: Actually the result I ultimately need is array([1, 2, 3]). I'm adding a line in a comment on the selected answer to address this.
推荐答案
list.如果您执行list(chain)，它将正常工作.但是，仅将其用于调试目的，通常效率低下.
list. If you do list(chain) it should work. But use this just for debugging purposes, it could be inefficient in general.
这篇关于从itertools.chain对象获取一个数组的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！