问题描述
我遇到了一个家庭作业问题，该问题要求我询问用户1位数到5位数之间的数字(例如，他们可以输入1、12、123、1234)，我知道如何使用循环，然后使用mov ah，1h函数询问用户他们想要的数字，但是我想接受用户的输入(例如123)，然后将该数字存储在我创建的变量Y中然后，我想处理它，我已经知道如何处理数字，但是只有当我已经在变量中声明了数字(Y dw 123)时，但是由于我必须要求用户输入，所以我保留未初始化的变量(Y dw?).现在，由于卡住了，我决定只创建它，而不是创建"Y dw?"，"Y dw 0,0,0,0,0"，因此我可以手动将输入数字存储到该Y变量中./p>
基本上，我想知道如何将用户输入的每个数字存储在我的Y变量中，即使它是"Y dw 123"，也可以在其中使用它
这是我到目前为止所拥有的:
title lab6 (lab6.asm)
.model small
.stack 100h
.data
Y dw 0,0,0,0,0 ,0dh, 0ah
W dw ?
Sum dw ?
printSum db "The Sum is: "
sumMessage db 0,0,0,0,0 ,0dh, 0ah
printW db "W is: "
wMessage db 0,0,0,0,0 ,0dh, 0ah, '$'
.code
main proc
mov ax,@data
mov ds,ax
mov bx, 0
mov si, 1
loop1:
mov ax, 0
mov ah, 1h
int 21h
cmp al, 0dh
je endloop
mov bl, al
mov Y+si, ax
inc si
loop loop1
endloop:
mov ax, 0
mov Y, bx
mov ax,Y ;Store Y in ax register
sub ax,1
mov Y, ax
mov ax, 0
mov Sum,36 ; add 36 to Sum
mov bx,Y
add Sum,bx ; add 36 and Y into Sum
mov ax,Y
mov bx,4 ; take Y and divide by 4
mov dx,0
idiv bx
add Sum,ax
mov ax,Y ;take Y and divide by 100
mov bx,100
mov dx,0
idiv bx
add Sum,ax
mov bx,7
mov dx,0 ; calculate W
idiv bx
mov W,dx
add W,1
mov dx, W
add dl, 30h
mov wMessage+1, dl
mov ax, 0
mov dx, 0
mov ax,Sum
mov cx, 10 ;start modding the number 2553
idiv cx
mov si, 4
sumLoop: ;Loop to mod and store 2553 into sumMessage
add dl, 30h
mov sumMessage+[si], dl
mov dx, 0
mov cx, 10
idiv cx
dec si
cmp si, 0h
je endSum
loop sumLoop
endSum:
mov si, 0
mov cl, printSum
L1: ;Loop to print out "Sum is : 2553
mov al, 0
mov al, printSum[si]
inc si
cmp al, '$'
je end_loop
mov dl, al
mov ah, 2h
int 21h
loop L1:
end_loop:
mov ax,4C00h
int 21h
main endp
end main
对于我现在拥有的代码，如果我输入123作为用户输入，它给我的总和是:0098，而W是1，事实并非如此，总和实际上应该是0189，并且W是6.另外，我也很想知道如何取出开头的0.
这是此作业的说明:
编写一个计算以下内容的程序:
Y =(获取用户输入)
Y = Y-1
总和= 36 + Y +(Y/4)+(Y/100)
W =总和％7 + 1
输出W，总和
注意:您不得使用任何库函数
如果我的问题仍然不清楚，请告诉我，以便我可以尝试清楚地问我的问题，以便其他人可以理解.
谢谢！
尝试类似这样的操作以输入数字:
mov cx, 10
mov bx, 0
loop1:
mov ax,0100h
int 21h
cmp al,0dh
je endloop
and ax,0fh
xchg ax,bx
mul cx
add bx,ax
jmp loop1
endloop:
mov Y, bx
I am stuck on a problem I have for a homework assignment that is asking me to ask the user fora digit ranging from 1 digit to 5 digits (eg. they can input 1, 12, 123, 1234) I know how to ask the user for whatever number they want, using a loop and then using the mov ah, 1h function, but I want to take the user's input, let's say 123, and then store that number in a variable that I've created, Y. Then I want to process it, I already know how to process the number, but only when I've already declared the number in the variable ( Y dw 123), but since I have to ask the user for an input, I have to leave the variable uninitialized ( Y dw ?). Now since I was stuck I decided to just create this instead of "Y dw ?", "Y dw 0,0,0,0,0", I did this so that I can manual store enter number into that Y variable.
Basically, I am wondering how I can take each number the user inputs and store it in my Y variable where I can use it just if it was "Y dw 123"
Here is what I have so far:
title lab6 (lab6.asm)
.model small
.stack 100h
.data
Y dw 0,0,0,0,0 ,0dh, 0ah
W dw ?
Sum dw ?
printSum db "The Sum is: "
sumMessage db 0,0,0,0,0 ,0dh, 0ah
printW db "W is: "
wMessage db 0,0,0,0,0 ,0dh, 0ah, '$'
.code
main proc
mov ax,@data
mov ds,ax
mov bx, 0
mov si, 1
loop1:
mov ax, 0
mov ah, 1h
int 21h
cmp al, 0dh
je endloop
mov bl, al
mov Y+si, ax
inc si
loop loop1
endloop:
mov ax, 0
mov Y, bx
mov ax,Y ;Store Y in ax register
sub ax,1
mov Y, ax
mov ax, 0
mov Sum,36 ; add 36 to Sum
mov bx,Y
add Sum,bx ; add 36 and Y into Sum
mov ax,Y
mov bx,4 ; take Y and divide by 4
mov dx,0
idiv bx
add Sum,ax
mov ax,Y ;take Y and divide by 100
mov bx,100
mov dx,0
idiv bx
add Sum,ax
mov bx,7
mov dx,0 ; calculate W
idiv bx
mov W,dx
add W,1
mov dx, W
add dl, 30h
mov wMessage+1, dl
mov ax, 0
mov dx, 0
mov ax,Sum
mov cx, 10 ;start modding the number 2553
idiv cx
mov si, 4
sumLoop: ;Loop to mod and store 2553 into sumMessage
add dl, 30h
mov sumMessage+[si], dl
mov dx, 0
mov cx, 10
idiv cx
dec si
cmp si, 0h
je endSum
loop sumLoop
endSum:
mov si, 0
mov cl, printSum
L1: ;Loop to print out "Sum is : 2553
mov al, 0
mov al, printSum[si]
inc si
cmp al, '$'
je end_loop
mov dl, al
mov ah, 2h
int 21h
loop L1:
end_loop:
mov ax,4C00h
int 21h
main endp
end main
For the code that I have now if I enter 123 as the user input it gives me that the Sum is : 0098, and W is 1, which shouldn't be the case, the Sum should actually be 0189, and the W is 6. Also I was wondering how I would take out the leading 0's.
Here are the instructions for this assignment:
Write a program that computes the following:
Y = (Get user input)
Y= Y-1
Sum = 36 + Y + (Y/4) + (Y/100)
W = Sum % 7 + 1
Output W, Sum
Note: You may not use any library functions
If my question is still unclear please tell me so I may attempt to ask my question clearly so what others may understand.
Thanks!
Try something like this to input a number:
mov cx, 10
mov bx, 0
loop1:
mov ax,0100h
int 21h
cmp al,0dh
je endloop
and ax,0fh
xchg ax,bx
mul cx
add bx,ax
jmp loop1
endloop:
mov Y, bx
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