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问题描述
我希望能够动态构建"一个 numpy 数组,但我事先不知道这个数组的大小.
I want to be able to 'build' a numpy array on the fly, I do not know the size of this array in advance.
例如我想做这样的事情:
For example I want to do something like this:
a= np.array()
for x in y:
a.append(x)
这将导致 a 包含 x 的所有元素,显然这是一个微不足道的答案.我只是好奇这是否可能?
Which would result in a containing all the elements of x, obviously this is a trivial answer. I am just curious whether this is possible?
推荐答案
构建 Python 列表并将其转换为 Numpy 数组.每次追加需要分摊 O(1) 时间 + O(n) 转换为数组,总共 O(n).
Build a Python list and convert that to a Numpy array. That takes amortized O(1) time per append + O(n) for the conversion to array, for a total of O(n).
a = []
for x in y:
a.append(x)
a = np.array(a)
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