问题描述
我正在尝试编写一个利用sobel过滤器检测图像边缘的程序.因此,首先,我用一些基本代码写下了一些要求,例如将x和y方向过滤器作为数组,并尝试读取pgm图像:
I'm attempting to write a program that utilizes the sobel filter to detect edges in images. So first off, I've written down some of the requirements in some basic code, such as the x and y direction filters as arrays and also an attempt to read in a pgm image:
program edges
implicit none
integer, dimension(:,:), allocatable :: inp, outim, GX, GY
integer, parameter :: dp = selected_real_kind(15,300)
integer :: ky, kx, x, y, out_unit = 10, M, N, sx, sy, i, j
real(kind=dp) :: G
M = 5
N = 5
allocate(inp(M,N))
allocate(outim(M-2,N-2))
allocate(GX(3,3))
allocate(GY(3,3))
open(file = 'clown.pgm',unit=out_unit,status= 'unknown') !opening file to write to inp
read (out_unit,11) 'P2' !pgm magic number
read (out_unit,12) 50,50 !width, height
read (out_unit,13) 1 !max gray value
do M=-25,25
do N=-25,25
read (out_unit,*) inp(M,N)
end do
end do
11 format(a2)
12 format(i3,1x,i3)
13 format(i5)
这是我第一次使用FORTRAN进行图像处理,除了将图像打印为pbm文件之外.读取图像的代码是我以前打印出的图像的副本,但我将写入改为读取.
This is my first time working with image manipulation in FORTRAN, apart from once when I printed an image out as a pbm file. The code for reading the image in is a replicate of what I used to print one out before, except I changed write to read.
所以我的问题是,如何将pgm格式的图像读入"inp"数组,以便可以应用sobel过滤器?进行尝试时,出现以下错误:
So my question is, how can I read in an image that's in pgm format into the "inp" array, so that I can apply the sobel filter? When I run my attempt, I get the following errors:
read (out_unit,11) 'P2' !pgm magic number
1
Error: Expected variable in READ statement at (1)
sobel.f90:41:18:
read (out_unit,12) 50,50 !width, height
1
Error: Expected variable in READ statement at (1)
sobel.f90:42:18:
read (out_unit,13) 1 !max gray value
1
Error: Expected variable in READ statement at (1)
谢谢
推荐答案
第一个错误是,正如编译器非常清楚地指出的那样,在此行中:
The first mistake is, as the compiler states quite clearly, in this line:
read (out_unit,11) 'P2'
编译器希望,因为这是Fortran的定义方式,因此会被告知将out_unit
中的值读入变量,但是'P2'
是字符文字(或标准调用的内容),这是一个字符串,不是一个变量.
The compiler expects, because that's the way that Fortran is defined, to be told to read a value from out_unit
into a variable, but 'P2'
is a character literal (or whatever the heck the standard calls them), it's a string, it's not a variable.
下一行也发生相同的错误.编译器期望像
The same mistake occurs in the next lines too. The compiler expects something like
integer :: p2 ! pgm magic number
...
read (out_unit,11) p2
等.执行此版本的read语句后,变量p2
保留从pgm
文件读取的幻数.
etc. After execution of this version of the read statement the variable p2
holds the magic number read from the pgm
file.
我正在写的时候,调用要从out_unit
中读取的单元只是错误的,最终会使您感到困惑.
While I'm writing, calling the unit to be read from out_unit
is just perverse and will, eventually, confuse you.
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