问题描述
我为这个问题创建了一个聊天:这里
我有一个视图试图执行 f = open('textfile.txt', 'w')
但在我的实时服务器上,这带来了错误 [Errno 13] 权限拒绝:'textfile.txt'
.
我的文件结构如下:
- 根|- 项目|- 应用程序|- 媒体
视图在 app
中的位置.
我曾尝试让 textfile.txt 存在于 root、项目、应用程序和媒体中,所有这些都具有 777 个文件权限(所有者、组和公众可以读取、写入和执行)[*1].
如果我将命令更改为读取权限,即 f = open('textfile.txt', 'r')
我得到同样的错误.
我的媒体根设置为 os.path.join(os.path.dirname(__file__), 'media').replace('\','/')
而这一切都是通过 webfaction 在 apache 服务器上运行的.
所以我有两个问题.django/python 试图从哪里打开这个文件?以及我需要更改什么才能获得视图打开和写入文件的权限.
[*1] 我知道这不是一个好主意,我只是为了当前的调试目的设置了这个.
我不知道这是否相关,但现在当我将其更改为 f = open(os.path.join(settings.MEDIA_URL, 'textfile.txt'), 'r')
而不是 f = open(os.path.join(settings.MEDIA_URL, 'textfile.txt'), 'w')
我收到错误 [Errno 2] No such file or目录
.
我不知道这是否有意义...
鉴于以下内容:
f = open('textfile.txt', 'w')
它应该在与 __file__
、当前运行的脚本或 views.py
相同的目录中创建文件.>
然而,最好是明确的,因此排除任何潜在的偏差.我建议将该行更改为:
导入操作系统f = open(os.path.join(os.path.dirname(__file__), 'textfile.txt'), 'w')
或者甚至更好,例如:
导入操作系统从 django.conf 导入设置f = open(os.path.join(settings.MEDIA_ROOT, 'textfile.txt'), 'w')
然后,您始终可以确定确切文件的保存位置,这应该允许您更适当地优化您的权限.或者,您可以使用 PROJECT_ROOT
.
I've created a chat for this question: here
I have a view that attempts to execute f = open('textfile.txt', 'w')
but on my live server this brings up the error [Errno 13] Permission denied: 'textfile.txt'
.
My file structure is as follows:
- root
|
- project
|
- app
|
- media
where the view lives in app
.
I have tried having textfile.txt live in root, project, app and media all of which have 777 file permissions (owner, group and public can read, write and execute)[*1].
If I change the command to a read permission ie f = open('textfile.txt', 'r')
I get the same error.
My media root is set to os.path.join(os.path.dirname(__file__), 'media').replace('\','/')
and this is all running on an apache server through webfaction.
So I have two questions. Where is django/python trying to open this file from? and what do I need to change to get permission for the view to open and write to the file.
[*1] I know this is not a good idea, I just have this set for current debugging purposes.
EDIT:
I don't know if this is relevant but now when I change it to f = open(os.path.join(settings.MEDIA_URL, 'textfile.txt'), 'r')
rather than f = open(os.path.join(settings.MEDIA_URL, 'textfile.txt'), 'w')
I get the error [Errno 2] No such file or directory
.
I don't know if this has meaning or not...
Given the following:
f = open('textfile.txt', 'w')
It should be creating the file in same directory as __file__
, the currently running script or views.py
in your scenario.
However, it's better to be explicit, and therefore rule out any potential deviations. I'd recommend changing that line to:
import os
f = open(os.path.join(os.path.dirname(__file__), 'textfile.txt'), 'w')
Or even better, something like:
import os
from django.conf import settings
f = open(os.path.join(settings.MEDIA_ROOT, 'textfile.txt'), 'w')
Then, you're always assured exactly where the file is being saved, which should allow you to optimize your permissions more appropriately. Alternatively, you can use a PROJECT_ROOT
.
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