问题描述
例子:= [] int {1, 25,3,5,4}
sort.Ints(example)//这会给我一个从1到最高数字的分片
我如何对它进行排序,使其从最高到最低?所以[25 5 4 3 1]
我试过这个
sort.Sort(sort.Reverse(sort.Ints(keys)))
来源:
然而,我收到了下面的错误:
#command-line-arguments
./Roman_Numerals.go: 31:sort.Ints(keys)用作值
是一种便捷的函数,用于对几个整数进行排序。一般来说,如果您想对某些内容进行排序并且只是返回该接口的一个不同实现,它重新定义了 Less
方法。
幸运的是,排序包中包含一个名为的预定义类型,用于实现排序。接口:
键:= [] int {3,2,8,1}
sort.Sort sort.Reverse(sort.IntSlice(keys)))
fmt.Println(keys)
I am trying to reverse-sort a slice of integers in Go.
example := []int{1,25,3,5,4}
sort.Ints(example) // this will give me a slice sorted from 1 to the highest number
How do I sort it so that it goes from highest to lowest? so [25 5 4 3 1]
I have tried this
sort.Sort(sort.Reverse(sort.Ints(keys)))
Source: http://golang.org/pkg/sort/#Reverse
However, I am getting the error below
# command-line-arguments
./Roman_Numerals.go:31: sort.Ints(keys) used as value
sort.Ints is a convenient function to sort a couple of ints. Generally you need to implement the sort.Interface interface if you want to sort something and sort.Reverse just returns a different implementation of that interface that redefines the Less
method.
Luckily the sort package contains a predefined type called IntSlice that implements sort.Interface:
keys := []int{3, 2, 8, 1}
sort.Sort(sort.Reverse(sort.IntSlice(keys)))
fmt.Println(keys)
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