问题描述
为什么这code
public class SponsoredComparator implements Comparator<SRE> {
public boolean equals(SRE arg0, SRE arg1){
return arg0.getSponsored()==arg1.getSponsored();
}
public int compare(SRE object1, SRE object2) {
Log.d("SponsoredComparator","object1.getName() == "+ object1.getName());
Log.d("SponsoredComparator","object1.getSponsored() == "+ object1.getSponsored());
Log.d("SponsoredComparator","object2.getName() == "+ object2.getName());
Log.d("SponsoredComparator","object2.getSponsored() == "+ object2.getSponsored());
Log.d("SponsoredComparator","compare return == "+ (object1.getSponsored() && object2.getSponsored() ? 0 : object1.getSponsored() ? -1 : 1));
return object1.getSponsored() && object2.getSponsored() ? 0 : object1.getSponsored() ? -1 : 1;
}
}
抛出此异常: ERROR / AndroidRuntime(244):java.lang.IllegalArgumentException异常:比较法违反其总承包
ERROR / AndroidRuntime(4446):在java.util.TimSort.mergeLo(TimSort.java:743)
throw this exception: ERROR/AndroidRuntime(244): java.lang.IllegalArgumentException: Comparison method violates its general contract!
ERROR/AndroidRuntime(4446): at java.util.TimSort.mergeLo(TimSort.java:743)
该方法sre.getSponsored()返回一个布尔值。
The method sre.getSponsored() returns a boolean.
感谢。
推荐答案
我怀疑当的没有的值赞助出现问题。这将返回1无论你叫它,即
I suspect the problem occurs when neither value is sponsored. That will return 1 whichever way you call it, i.e.
x1.compare(x2) == 1
x2.compare(x1) == 1
这是无效的。
我建议你改变这一点:
object1.getSponsored() && object2.getSponsored()
到
object1.getSponsored() == object2.getSponsored()
在这两个地方。我可能会的实际上的提取该用的地方这种签名的方法:
in both places. I would probably actually extract this out a method with this signature somewhere:
public static int compare(boolean x, boolean y)
然后调用它是这样的:
and then call it like this:
public int compare(SRE object1, SRE object2) {
return BooleanHelper.compare(object1.getSponsored(), object2.getSponsored());
}
这将使code更清晰,海事组织。
That will make the code clearer, IMO.
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