从EditText上与数据库中的字符串比较文本

问题描述

这code应该比较文本输入的 R.id.editUserName 是 R.string.DB_username ，如果他们匹配，在您登录，否则秀举杯，他们不匹配。

This code should compare text entered into R.id.editUserName with R.string.DB_username and, if they match, log you in, else show a toast that they don't match.

public void signIn(View view) {

  EditText editUserName = (EditText)findViewById(R.id.editUserName);
  String userName = editUserName.getText().toString();

  if ( userName ==  getResources().getString(R.string.DB_username)) {
    // log in
    setContentView(R.layout.screen1);
  } else {
    // show toast
    Toast toast = Toast.makeText(getApplicationContext(), userName+" != "+getResources().getString(R.string.DB_username), Toast.LENGTH_LONG);
    toast.setGravity(Gravity.CENTER, 0, 0);
    toast.show();
  }
}

即使当他们这样做匹配，它仍然显示敬酒，如罗杰！罗杰=...怎么会这样呢？

Even when they do match, it still shows a toast, such as "Roger != Roger"... how could that be?

推荐答案

不要对它们进行比较像。使用Java提供的字符串比较函数来比较它们。

Dont compare them like that. Use the string comparison function provided by java to compare them.

这里指：

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