本文介绍了类型中的方法不适用于参数的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我收到此错误消息:
发现 2 个错误:
错误:PayCalculator 类型中的方法确定TaxRate(double)不适用于参数 ()
错误:类型中的方法calculateNetPay(double, double)PayCalculator 不适用于参数 ()
Error: The method calculateNetPay(double, double) in the type PayCalculator is not applicable for the arguments ()
你能告诉我如何解决这个问题吗?
Can you tell me what to do to fix this?
public class PayCalculator
{
private double hourlyRate;
private double hoursWorked;
/**
* Two parameter constructor
* Add hourlyRate and hoursWorked
* @param the hourly rate
* @param the hours worked
*/
public PayCalculator(double aHourlyRate, double aHoursWorked)
{
hourlyRate = aHourlyRate;
hoursWorked = aHoursWorked;
}
/**
* sets the hourly rate
* @return hourlyRate
*/
public void setHourlyRate(double aHourlyRate)
{
hourlyRate = aHourlyRate;
}
/**
* gets the hourly rate
* @param hourlyRate
*/
public double getHourlyRate()
{
return hourlyRate;
}
/**
* sets the hours worked
* @return hoursWorked
*/
public void setHoursWorked(double aHoursWorked)
{
hoursWorked = aHoursWorked;
}
/**
* gets the hours worked
* @param hours worked
*/
public double getHoursWorked()
{
return hoursWorked;
}
public boolean workedOvertime()
{
if (hoursWorked > 40)
{
return true;
}
else
{
return false;
}
}
public double numHoursOvertime()
{
if (hoursWorked > 40)
{
return hoursWorked - 40;
}
else
{
return 0;
}
}
public double calculateGrossPay()
{
if (hourlyRate <= 10.25)
{
if (hourlyRate <= 40)
return hourlyRate * hoursWorked;
}
else
{
double grossPay = ((40 * hourlyRate) + ((hourlyRate * 2) * hoursWorked - 40));
return grossPay;
}
if (hoursWorked <= 60)
{
return hourlyRate * hoursWorked;
}
else
{
return 60 * hourlyRate;
}
}
public double determineTaxRate(double grossPay)
{
if (grossPay >= 800)
{
double tax = 0;
tax = grossPay * 0.37;
return tax;
}
else if ( grossPay >= 400)
{
double tax = 0;
tax = grossPay * 0.22;
return tax;
}
else
{
double tax = 0;
tax = grossPay * 0.12;
return tax;
}
}
public double calculateNetPay(double grossPay, double tax)
{
double calculateNetPay = grossPay - tax;
return calculateNetPay;
}
public void printData()
{
System.out.println("Hours Worked: " + hoursWorked);
System.out.println("Hourly rate: " + hourlyRate);
System.out.println("Number of hours of overtime worked: " + numHoursOvertime());
System.out.println("Worked overtime? " + workedOvertime());
System.out.println("Gross pay: " + calculateGrossPay());
System.out.println("Tax Rate: " + determineTaxRate());
System.out.println("Net Pay: " + calculateNetPay());
}
}
推荐答案
您正在致电
determineTaxRate()
但是你的方法是这样定义的:
But your method is defined as this:
public double determineTaxRate(double grossPay)
{
与您的其他错误相同.您需要将 double
传递给该方法.比如这个:
Same with your other error. You need to pass a double
to the method. Such as this:
determineTaxRate(calculateGrossPay())
这篇关于类型中的方法不适用于参数的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!