如何在Storyboard中的任何ViewController之外设计单独的UIView？

问题描述

我想设计一个UIView，它比Storyboard（iOS 5）中的ViewController大。

I would like to design a UIView, which is larger than a ViewController in Storyboard (iOS 5).

UIView应该用作UIScrollView的子视图因此比我现有的任何ViewControllers都要大。如何在Storyboard中创建这样的UIView并将其与我的UIScrollView相关联？

The UIView should be used as the subview of a UIScrollView and hence be larger than any of my existing ViewControllers. How can I create such a UIView in Storyboard and associate it with my UIScrollView?

如果可能，我想在没有xib文件的情况下这样做。

I would like to do this without xib files if possible.

谢谢！

推荐答案

除了使用xib之外我没有其他选择，但这并不是那么烦人：

I see no other option than using xibs, but it's not that annoying:

//We have file called "View.xib" in our project. It contains one SINGLE view
NSArray *xibContents = [[NSBundle mainBundle] loadNibNamed:@"View" owner:self options:nil];
UIView *view = [xibContents lastObject]; //safer than objectAtIndex:0

[self.scrollview addSubview:view];
self.scrollview.contentSize = view.frame.size; 

为了建立IB连接，您可以设置 filesOwner 在xib中的类是你的viewController，并像往常一样连接。

In order to make IB connections you can set the filesOwner class in the xib to be your viewController, and connect like usual.

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