问题描述
我有一个国画家的20张图片的文件，并与他们网站的文本文件。我想显示4排5列的表使用PHP此数据。
我尝试使用foreach循环迭代数组中每5个元素
（一个装载每行一个）
的foreach（array_chunk（$ CountryArtists，5，真）为$值）{
＆LT;表＆gt;
＆所述; TR＆GT;＆下; TD＆GT; $ CountryArtists [$值] $ ArtistImages [$值]＆LT; / TD＆GT;
＆所述; TD＆GT; $ CountryArtists [$值] $ ArtistImages [$值]＆LT; / TD＆GT;
＆所述; TD＆GT; $ CountryArtists [$值] $ ArtistImages [$值]＆LT; / TD＆GT;
＆所述; TD＆GT; $ CountryArtists [$值] $ ArtistImages [$值]＆LT; / TD＆GT;
＆所述; TD＆GT; $ CountryArtists [$值] $ ArtistImages [$值]＆LT; / TD＆GT;＆LT; / TR＆GT;
＆LT; /表＆gt;
我一直试图弄清楚如何将图像加载到数组，但有没有运气。即时通讯开始认为我必须把引用数组中的文件的位置，但我不知道。
$ colsToDisplay = 5;
$ CountryArtists =阵列（C：\\用户\\ THEFOLDER \\图像）;
$ ArtistImages =阵列（AJackson，BShelton，CUnderwood，DBentley，DLJones，德鲁克，JAldean，JCash，JJohnson，JStrait，KChesney， LAntebellum，LDavis，LRimes，MLambert，MMcBride，RTravis，STwain，TKeith，TMcgraw）;
$文件名=C：\\用户\\ THEFOLDER \\图像;
我是比较新的PHP和真的只需要知道如何加载我的图片，以及如何使该表显示正常。
编辑：
我添加回声表线，但它只是显示在浏览器中输出的回声：
回声$ CountryArtists [$值] $ ArtistImages [$值]回声。$ CountryArtists [$价值。 $ ArtistImages [$值]回声。$ CountryArtists [$价值。 $ ArtistImages [$值]回声。$ CountryArtists [$价值。 $ ArtistImages [$值]回声。$ CountryArtists [$价值。 $ ArtistImages [$值]回声}＆GT？;
我的code现在看起来是这样的：
的foreach（array_chunk（$ CountryArtists，5，真）为$值）{
回声＆LT;表＆gt;
回声＆LT; TR＆GT;＆LT; TD＆GT; $ CountryArtists [$值] $ ArtistImages [$值]＆LT; / TD＆gt;中
回声＆LT; TD方式＆gt; $ CountryArtists [$值] $ ArtistImages [$值]＆LT; / TD＆gt;中
回声＆LT; TD方式＆gt; $ CountryArtists [$值] $ ArtistImages [$值]＆LT; / TD＆gt;中
回声＆LT; TD方式＆gt; $ CountryArtists [$值] $ ArtistImages [$值]＆LT; / TD＆gt;中
回声＆所述; TD方式＆gt; $ CountryArtists [$值] $ ArtistImages [$值]＆下; / TD＆GT;＆下; / TR＆gt;中
回声＆LT; /表＆gt;
}
我觉得我做的不对强，会如此感激有它指给我看。
完整的文件
＆LT;！DOCTYPE HTML＆GT;
＆LT; HTML和GT;
＆LT;身体GT;＆LT; PHP
$ ArtistImages =阵列（AJackson，BShelton，CUnderwood，DBentley，DLJones，德鲁克，JAldean，JCash，JJohnson，JStrait，KChesney， LAntebellum，LDavis，LRimes，MLambert，MMcBride，RTravis，STwain，TKeith，TMcgraw）;
$数= COUNT（$ ArtistImages）;
$ COLS = 6;
$ DIV =（int）的$数/（INT）$ COLS;
$差异= CEIL（$ DIV）;
回声
$鳍= $ COLS * $差异;$ A = 1;
呼应'＆LT;表＆gt;';
为（$ I = 0; $ I＆LT; $鳍; $ I ++）{
如果（$ A == 1）
回声\\ T＆LT; TR＆gt;中。PHP_EOL; $艺术家=（！空（$ ArtistImages [$ i]））？ $ ArtistImages [$ i]：;
回声\\ t \\ t的。'＆LT; TD＆GT;'。$艺术家。'＆LT; / TD＆GT;'PHP_EOL。 如果（$ A == $ COLS）{
回声\\ T＆LT; / TR＆gt;中。PHP_EOL;
$ A = 0;
} $ A ++;
}
呼应'＆LT; /表＆gt;';
？＆GT;＆LT; /身体GT;
＆LT; / HTML＆GT;
我想你可能会寻找类似这种算法的东西。它增加了一个排，每5值。你会希望做一个除数使其 CEIL（），使其添加任何需要的空单元格。如果你这样做，你可以做到这一点的foreach ＆LT; UL＆GT; 和＆LT;李＆GT; 和使用CSS来让他们显示象表。然后，你不需要额外的计算单元。
$ I = 1;
呼应'＆LT;表＆gt;';
的foreach（$数组作为$值）{
如果（$ I == 1）
回声＆LT; TR＆gt;中; 呼应'＆LT; TD＆GT;'$价值。'＆LT; / TD＆GT;'; 如果（$ I == 5）{
回声＆LT; / TR＆gt;中;
$ I = 0;
} $ I ++;
}
呼应'＆LT; /表＆gt;';
编辑：
下面是一个基于你一个更实际的版本：
$ ArtistImages =阵列（AJackson，BShelton，CUnderwood，DBentley，DLJones，德鲁克，JAldean，JCash， JJohnson，JStrait，KChesney，LAntebellum，LDavis，LRimes，MLambert，MMcBride，RTravis，STwain，TKeith，TMcgraw）;//计数数组总艺术家
$数= COUNT（$ ArtistImages）;
//选择多少每行显示
$ COLS = 6;
//除以列的总
$ DIV =（int）的$数/（INT）$ COLS;
//四舍五入（柜面数量将产生空白单元格
$差异= CEIL（$ DIV）;
// Mulitply最终的数字
$鳍= $ COLS * $差异;
//创建一个autoincrementer跟踪下一行
$ A = 1;
呼应'＆LT;表＆gt;'PHP_EOL。
为（$ I = 0; $ I＆LT; $鳍; $ I ++）{
如果（$ A == 1）
回声\\ T＆LT; TR＆gt;中。PHP_EOL;
//你需要看是否填充这个艺术家。如果没有，请空
//如果没有这个离开它会有一个警告，不存在
$艺术家=（！空（$ ArtistImages [$ i]））？ $ ArtistImages [$ i]：;
回声\\ t \\ t的。'＆LT; TD＆GT;'。$艺术家。'＆LT; / TD＆GT;'PHP_EOL。
如果（$ A == $ COLS）{
回声\\ T＆LT; / TR＆gt;中。PHP_EOL;
$ A = 0;
} $ A ++;
}
呼应'＆LT; /表＆gt;';
I have a file with 20 pictures of country artists, and a text file with their websites. I'm trying to display this data in a 4 row 5 column table using PHP.
I try to use a foreach loop that iterates for every 5 elements in the array(to load each row one by one)
foreach(array_chunk($CountryArtists, 5, true) as $Value) {
<table>
<tr><td> $CountryArtists[$Value] $ArtistImages[$Value]</td>
<td> $CountryArtists[$Value] $ArtistImages[$Value]</td>
<td> $CountryArtists[$Value] $ArtistImages[$Value]</td>
<td> $CountryArtists[$Value] $ArtistImages[$Value]</td>
<td> $CountryArtists[$Value] $ArtistImages[$Value]</td></tr>
</table>
Ive been trying to figure out how to load the images into the array, but having no luck. Im starting to think i must put the reference to the file location in the array,but i am not sure.
$colsToDisplay = 5;
$CountryArtists = array("C:\Users\THEFOLDER\images");
$ArtistImages = array("AJackson", "BShelton", "CUnderwood", "DBentley", "DLJones", "DRucker", "JAldean", "JCash", "JJohnson", "JStrait", "KChesney", "LAntebellum", "LDavis", "LRimes", "MLambert", "MMcBride", RTravis", "STwain", TKeith", TMcgraw");
$filename = "C:\Users\THEFOLDER\images";
I'm relatively new to PHP and really just need to know how to load my images and how to make this table show up correctly.
EDIT:
I added echo to the table lines but it just shows echo in the browser output:
" echo " $CountryArtists[$Value] $ArtistImages[$Value]" echo " .$CountryArtists[$Value]. $ArtistImages[$Value]" echo " .$CountryArtists[$Value]. $ArtistImages[$Value]" echo " .$CountryArtists[$Value]. $ArtistImages[$Value]" echo " .$CountryArtists[$Value]. $ArtistImages[$Value]" echo "" } ?>
My code now looks like this:
foreach(array_chunk($CountryArtists, 5, true) as $Value) {
echo "<table>"
echo "<tr><td> $CountryArtists[$Value] $ArtistImages[$Value]</td>"
echo "<td> .$CountryArtists[$Value]. $ArtistImages[$Value]</td>"
echo "<td> .$CountryArtists[$Value]. $ArtistImages[$Value]</td>"
echo "<td> .$CountryArtists[$Value]. $ArtistImages[$Value]</td>"
echo "<td> .$CountryArtists[$Value]. $ArtistImages[$Value]</td></tr>"
echo "</table>"
}
I feel like I'm doing strong wrong, would be so grateful to have it pointed out to me.
FULL FILE
<!DOCTYPE HTML>
<html>
<body>
<?php
$ArtistImages = array("AJackson", "BShelton", "CUnderwood", "DBentley", "DLJones", "DRucker", "JAldean", "JCash", "JJohnson", "JStrait", "KChesney", "LAntebellum", "LDavis", "LRimes", "MLambert", "MMcBride", "RTravis", "STwain", "TKeith", "TMcgraw");
$count = count($ArtistImages);
$cols = 6;
$div = (int) $count / (int)$cols;
$diff = ceil($div);
echo
$fin = $cols * $diff;
$a = 1;
echo '<table>';
for($i = 0; $i < $fin; $i++) {
if($a == 1)
echo "\t<tr>".PHP_EOL;
$artist = (!empty($ArtistImages[$i]))? $ArtistImages[$i]: "";
echo "\t\t".'<td>'.$artist.'</td>'.PHP_EOL;
if($a == $cols) {
echo "\t</tr>".PHP_EOL;
$a=0;
}
$a++;
}
echo '</table>';
?>
</body>
</html>
I think you may be looking for something similar to this algorithm. It adds a row every 5 values. You will want to do a divisor make it ceil() to make it add any required empty cells. You can do this foreach if you do <ul> and <li> and use CSS to make them display like a table. Then you don't need to calculate extra cells.
$i = 1;
echo '<table>';
foreach($array as $value) {
if($i == 1)
echo "<tr>";
echo '<td>'.$value.'</td>';
if($i == 5) {
echo "</tr>";
$i=0;
}
$i++;
}
echo '</table>';
EDIT:
Here is a more practical version based on yours:
$ArtistImages = array("AJackson", "BShelton", "CUnderwood", "DBentley", "DLJones", "DRucker", "JAldean", "JCash", "JJohnson", "JStrait", "KChesney", "LAntebellum", "LDavis", "LRimes", "MLambert", "MMcBride", "RTravis", "STwain", "TKeith", "TMcgraw");
// Count total artists in array
$count = count($ArtistImages);
// Choose how many to display per row
$cols = 6;
// Divide the total by the columns
$div = (int) $count / (int)$cols;
// Round up (incase the number will produce empty cells
$diff = ceil($div);
// Mulitply the final numbers
$fin = $cols * $diff;
// Create an autoincrementer to keep track of next rows
$a = 1;
echo '<table>'.PHP_EOL;
for($i = 0; $i < $fin; $i++) {
if($a == 1)
echo "\t<tr>".PHP_EOL;
// You need to see if this artist is populated. If not, make empty
// If left without this it will have a warning saying not exists
$artist = (!empty($ArtistImages[$i]))? $ArtistImages[$i]: "";
echo "\t\t".'<td>'.$artist.'</td>'.PHP_EOL;
if($a == $cols) {
echo "\t</tr>".PHP_EOL;
$a=0;
}
$a++;
}
echo '</table>';
这篇关于从显示的数据阵列在动态表PHP的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！