问题描述
任何人都知道如何在不使用递归的情况下根据文本查询向 twitter api 发出请求.
Anyone knows how can i make requests to twitter api based on text queries without using a recursion.
这是我的代码
function news_tweets(query, user_id, count) {
news_array = [];
user_tweets = [];
full_array = [];
$.getJSON("https://api.twitter.com/1/statuses/user_timeline.json?include_entities=true&include_rts=false&user_id=" + user_id +
"&count=" + count + "&callback=?",
function (data) {
$.each(data, function (i, item) {
var user = item.user.name;
var date = item.created_at;
var profile_img = item.user.profile_image_url;
var text = item.text;
var url = (item.entities.urls.length > 0 ? item.entities.urls[0].url : '');
news_array.push({
news_user: user,
news_date: date,
news_profile_img: profile_img,
news_text: text,
news_url: url
});
});
find_tweets(news_array);
});
}
function find_tweets(news_array) {
for (var i in news_array) {
var news_text = news_array[i].news_text;
$.getJSON("http://search.twitter.com/search.json?q=" + news_text +
"&rpp=10&include_entities=true&result_type=mixed&callback=?",
function (data) {
$.each(data.results, function (i, item) {
var user = item.from_user;
var user_id = item.from_user_id;
var date = item.created_at;
var user_profile_img = item.profile_image_url;
var text = item.text;
var url = (item.entities.urls.length > 0 ? item.entities.urls[0].url : '');
user_tweets.push({
user: user,
user_id: user_id,
date: date,
user_profile_img: user_profile_img,
text: text
});
});
combine_arrays(news_array, user_tweets);
});
}
function combine_arrays(news_array, user_tweets) {
full_array = news_array.concat(user_tweets); console.log(full_array);
}
}
当我使用 console.log("hello") 或尝试连接两个数组时,一切都执行了 3 次.
when i use console.log("hello") or try to connect the two arrays everything is executed three times.
推荐答案
您似乎只有 news_array
和 user_tweets
数组的一个实例.在那些上,您推送 api 查询的所有结果.然而,您从循环中对整个数组调用 combine_arrays
函数(每次搜索后都会为您提供一组新结果) - 在某些项目上运行多次.
You seem to have only one instance of the news_array
and user_tweets
arrays. On those, you push all the result of your api queries. Yet, you call the combine_arrays
function on the whole arrays from a loop (each time after the search gave you a new set of results) - running multiple times over some of the items.
我想重新初始化
var user_tweets = [];
在 find_tweets
函数中会有所帮助.
inside the find_tweets
function would help something.
不能访问回调外的ajax数据.相反,您需要等到所有异步请求都得到解决.我建议使用 jQuery 的延迟对象,这使得处理这些事情变得更加容易:
You can't access the ajax data outside the callback. Instead, you will need to wait until all the asynchronous requests are resolved. I recommend to use jQuery's Deferred object which makes handling such things much easier:
function news_tweets(query, user_id, count) {
var news_array = [],
user_tweets = [];
return $.getJSON("https://api.twitter.com/1/statuses/user_timeline.json", {
include_entities: "true",
include_rts: "false",
user_i: user_id,
count: count
}).then(function (data) {
return $.when.apply(null, $.map(data, function (item) {
news_array.push({
news_user: item.user.name,
news_date: item.created_at,
news_profile_img: item.user.profile_image_url,
news_text: item.text,
news_url: item.entities.urls.length ? item.entities.urls[0].url : ''
});
return $.getJSON("http://search.twitter.com/search.json", {
q: item.text,
rpp: 10,
include_entities: "true",
result_type: "mixed"
}).done(function (data) {
$.each(data.results, function (i, item) {
user_tweets.push({
user: item.from_user,
user_id: item.from_user_id,
date: item.created_at,
user_profile_img: item.entities.urls.length ? item.entities.urls[0].url : '',
text: item.text
});
});
});
}));
}).then(function() {
// this callback is executed [once] when all requests are done
// and the user_tweets array is filled
// arguments is an array of all search request results
var full_array = news_array.concat(user_tweets);
console.log(full_array);
return full_array;
})
}
用法:
news_tweets(…).done(function callback(full_array) {
// do something with all the objects
});
这篇关于如何在不输入递归的情况下请求 twitter api的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!