问题描述
我有以下代码,当长度为0时,防止用户输入空格。现在,如何防止用户在长度为0时输入所有特殊字符(除AZ AZ 0-9以外的任何其他字符)?
($'$ p$ b $ $ $ $ $''$'$'$'$' #DivisionName').val()。length == 0){
if(e.which == 32){// space bar
e.preventDefault();
}
}
});
这是我的文本框。
< input type =textid =DivisionName/>
字母和数字范围是(包含):
- 97 - 122(az)
- 65 - 90(AZ)
- 48 - 57(0-9)
这就是你比较 e.which 针对。
if(e.which< 48 ||
(e。其中> 57& e.which< 65)||
(其中> 90& e.which< 97)||
e.which>< 122){
e.preventDefault();
}
或者使用逆逻辑:
var valid =(e.which> = 48&& e.which< = 57)|| (即,其中> = 65&<< = 90)|| (例如> = 97& e。,其中 if(!valid){
e.preventDefault();
}
更新
$ b
即使如此,您仍然希望使用正则表达式来验证字段内容:
if(/^[A-Z0-9]+$/i.test(value)){
//现在好看
}
或者通过更换坏东西来修复该字段:
var stripped = value.replace(/ [^ A-Z0-9] + / i,'');
I have the following code which prevents user from entering space when the length is 0. Now, how can I prevent user from entering all special characters(anything other than a-z A-Z 0-9) when the length is 0?
$('#DivisionName').bind('keypress', function(e) { if($('#DivisionName').val().length == 0){ if (e.which == 32){//space bar e.preventDefault(); } } });
This is my text box.
<input type="text" id="DivisionName" />
The letter and digit ranges are (inclusive):
- 97 - 122 (a-z)
- 65 - 90 (A-Z)
- 48 - 57 (0-9)
This is what you compare e.which against.
if (e.which < 48 || (e.which > 57 && e.which < 65) || (e.which > 90 && e.which < 97) || e.which > 122) { e.preventDefault(); }
Or, using inverse logic:
var valid = (e.which >= 48 && e.which <= 57) || (e.which >= 65 && e.which <= 90) || (e.which >= 97 && e.which <= 122); if (!valid) { e.preventDefault(); }
Update
Even so, you may still wish to validate the field contents as a whole using a regular expression:
if (/^[A-Z0-9]+$/i.test(value)) { // it looks okay now }
Or fix the field by replacing the bad stuff:
var stripped = value.replace(/[^A-Z0-9]+/i, '');
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