本文介绍了Android的0nTouch事件问题[向下滑动和UP]的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
IM具有这就需要像iPhone onTouch刷卡事件的应用程序。他们是
im having an application which needs onTouch swipe events like in Iphone. they are
- 向上滑动。
- 向下滑动。
- 请向左滑动。
- 向右滑动即可。
我实现onTouch事件如下。我得到了左右滑动即可行动correctly.but这是贯彻落实刷卡正确的方式向下和向上的动作。
i implemented onTouch event as following . and i got Swipe Left and Right actions correctly.but which is the correct way to implement the swipe Down and Up actions.
我的code:
float downXValue,downYValue;
@Override
public boolean onTouchEvent(MotionEvent arg1) {
// Get the action that was done on this touch event
switch (arg1.getAction())
{
case MotionEvent.ACTION_DOWN:
{
// store the X value when the user's finger was pressed down
downXValue = arg1.getX();
downYValue = arg1.getY();
break;
}
case MotionEvent.ACTION_UP:
{
// Get the X value when the user released his/her finger
float currentX = arg1.getX();
float currentY=arg1.getY();
// going backwards: pushing stuff to the right
if (downXValue < currentX)
{
Log.d(DEBUG_TAG, "Right");
}
// going forwards: pushing stuff to the left
if (downXValue > currentX)
{
Log.d(DEBUG_TAG, "Left");
}
break;
}
}
//GestureListener is called here...
//return gestures.onTouchEvent(event);
return true;
}
感谢您。
推荐答案
什么...
if (downYValue < currentY)
{
Log.d(DEBUG_TAG, "Down");
}
您确定您写的code以上?
Are you sure you wrote the code above?
修改
好吧,我相信你。你所要做的主要是:
OK, I believe you. What you have to do is basically:
double sizeInX = Math.abs(downXValue - currentX);
double sizeInY = Math.abs(downYValue - currentY);
if( sizeInX > sizeInY ){
// you better swipe horizontally
} else {
// you better swipe vertically
}
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