将JSON响应从Ruby映射到Python

问题描述

:抱歉，我第一次没有足够详细地解释，因为我有点想自己解决其余的问题，但最终我变得更加困惑

我有一个小问题.我想利用网站的API JSON响应

I have a small problem.I wanted to take advantage of a website's API JSON response

{
    "Class": {
        "Id": 1948237,
        "family": "nature",
        "Timestamp": 941439
    },
    "Subtitles":    [
      {
        "Id":151398,
        "Content":"Tree",
        "Language":"en"
      },
      {
        "Id":151399,
        "Content":"Bush,
        "Language":"en"
      }
    ]
}

所以我想用每行字幕的组合字符串打印URL，并用换行符分隔

So I'd like to print the url with a combined string of each line of subtitles, seperated by newlines

我设法在Ruby中这样做:

And I manage to do so in Ruby like this:

def get_word
    r = HTTParty.get('https://example.com/api/new')
# Check if the request had a valid response.
    if r.code == 200
        json = r.parsed_response
        # Extract the family and timestamp from the API response.
        _, family, timestamp = json["Class"].values

        # Build a proper URL
        image_url = "https://example.com/image/" + family + "/" + timestamp.to_s

        # Combine each line of subtitles into one string, seperated by newlines.
        word = json["Subtitles"].map{|subtitle| subtitle["Content"]}.join("\n")

        return image_url, word
    end
end

但是现在我需要将其移植到python上，因为我对python很糟糕，所以我似乎还无法弄清楚.

However now I need to port this to python and because I'm terrible at python I can't really seem to figure it out.

我使用的是请求而不是HTTParty，因为我认为这是最好的选择.我尝试这样做:

I'm using requests instead of HTTParty as I think it's the best equivalent.I tried doing this:

def get_word():
  r = requests.request('GET', 'https://example.com/api/new')
  if r.status_code == 200:
      json = requests.Response
      # [DOESN'T WORK] Extract the family and timestamp from the API response.
      _, family, timestamp = json["Class"].values

      # Build a proper URL
      image_url = "https://example.com/image/" + family + "/" + timestamp.to_s

      # Combine each line of subtitles into one string, seperated by newlines.
      word = "\n".join(subtitle["Content"] for subtitle in json["Subtitles"])
      print (image_url + '\n' + word)

get_word()

但是，我在提取JSON响应并合并行方面陷入困境

However I get stuck at extracting the JSON response and combining the lines

推荐答案

您可能需要将传入的json转换为python字典

You might need to convert the incoming json to python dictionary

假设这是您的答复

#convert to dict
import json
json_data = json.loads(response)
# print content
for a_subtitle in response['Subtitles']:
    print(a_subtitle['content'])

# extract family and timestamp
family = json_data["Class"]["family"]
timestamp = json_data["Class"]["Timestamp"]
image_url = "https://example.com/image/" + family + "/" + str(timestamp)

这篇关于将JSON响应从Ruby映射到Python的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！