谁能在第47行发现错误

本文介绍了谁能在第47行发现错误的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述 我正在进行更新，并且在我的更新脚本中第47行遇到障碍，有一个错误，但无法发现它，一直在寻找它 也许第三只眼睛会看到我不能的，任何帮助都会非常感激。 我尝试了什么： b $ b I am doing an update and i keep hitting a snag on line 47 in my update script, there is an error there but cannot spot it, been looking for it whole daymaybe a third eye will see what i cannot, any help will be much appreciated.What I have tried:<pre><?phpif(isset($_POST['edit'])){//Capture values from form and store in php variables $title=$_POST['title']; $fname=$_POST['fname']; $address=$_POST['address']; $sex=$_POST['gender']; $hobbies=join(" ,", $_POST['hobby']); $uname=$_POST['uname']; $pword=$_POST['currentpword']; include'db_config.php'; $sql = "SELECT uname,pword FROM member WHERE uname='$uname' AND pword=md5('$pword')";if($result=mysqli_query($con,$sql)){$rowcount=mysqli_num_rows($result);if($rowcount==1){$sql="UPDATE member SET title='$title', name='$fname', address='$address', sex='$sex', hobby='$hobby', uname='$uname',WHERE pword=md5('$pword')";if(mysqli_query($con,$sql)){mysqli_close($con);echo "<script type=\"text/javascript\"> alert('your information has been updated $title $name'); window.location\view.php\"; </script>";}else{echo"<script type\"text/javascript\">alert('error');window.location/edit.php\";</script>";}else<--- the arrow point to where the error is. {echo mysqli_error($con);}}}?> 推荐答案 _POST [' edit']）） { // 从中捕获值在php变量中形成和存储 _POST['edit'])){//Capture values from form and store in php variables title = _POST [' title']; _POST['title']; 这篇关于谁能在第47行发现错误的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！