将ASCII std :: string转换为十六进制

问题描述

有一个简单的方法来将ASCII std :: string转换为HEX？我不想将其转换为一个数字，我只想将每个ASCII字符转换为它的十六进制值。输出格式也应该是std :: string。
ie：TEST将是0x54 0x45 0x53 0x54或一些类似的格式。

is there an easy way to convert an ASCII std::string to HEX? I don't want to convert it to a number, I only want to convert each ASCII character to it's HEX value. The output format should also be a std::string.i.e.: "TEST" would be "0x54 0x45 0x53 0x54" or some similar format.

我发现这个解决方案，但也许有一个更好的无字符串到字符串转换）：

I found this solution, but maybe there is a better one (without string to int to string conversion):

std::string teststring = "TEST";
std::stringstream hValStr;
for (std::size_t i=0; i < teststring.length(); i++)
{
    int hValInt = (char)teststring[i];
    hValStr << "0x" << std::hex << hValInt << " ";
}

感谢，

/ mspoerr

Thanks,
/mspoerr

推荐答案

如果你不关心0x，很容易使用 std :: copy ：

If you don't care about the 0x it's easy to do using std::copy:

#include <algorithm>
#include <sstream>
#include <iostream>
#include <iterator>
#include <iomanip>

namespace {
   const std::string test="hello world";
}

int main() {
   std::ostringstream result;
   result << std::setw(2) << std::setfill('0') << std::hex << std::uppercase;
   std::copy(test.begin(), test.end(), std::ostream_iterator<unsigned int>(result, " "));
   std::cout << test << ":" << result.str() << std::endl;
}

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