java prompt + get a string 包含任何空格(一个或多个)

问题描述

我需要从提示中获取一个字符串，然后在我需要从提示中获取一个字符串列表之后.我有个问题.当我拿到我的清单时，我只有第一个词.我尝试任何其他 nextLine() ......但不起作用.我看到很多样本只有 2 个单词(一个空格)，但我正在寻找一个单词列表！！

I need get a String from prompt, and juste after I need get a String list from prompt. I have a problem. When I get my list, I have only the first word. I try any other nextLine() ... but do not work. I see lot of sample with juste 2 words (one space) but i looking for a list of word!!

Java 代码:

public static void main(String[] args) {
    Scanner input = new Scanner(System.in);
    System.out.println("Enter a name:");
    String name = input.next();
    System.out.println("Enter a name list:");
    String nameList = input.next();
    System.out.println("Enter last name:");
    String lastName = input.next();
    input.close();
    System.out.println(name + " * " + nameList + " ** " + lastName);
}

控制台结果:

Enter a name:
aa
Enter a name list:
bb cc dd
Enter last name:
aa * bb ** cc

第一个响应是 aa + enter

1st response is aa + enter

第二个响应是 bb cc dd + enter

2nd response is bb cc dd + enter

但是在dd + enter之后，程序显示输入姓氏:aa * bb ** cc 并停止

but juste after dd + enter, the program display Enter last name:aa * bb ** cc and stop

推荐答案

solution .nextLine() 但在所有行

public static void main(String[] args) {
    Scanner input = new Scanner(System.in);
    System.out.println("Enter a name:");
    String name = input.nextLine();
    System.out.println("Enter a name list:");
    String nameList = input.nextLine();
    System.out.println("Enter last name:");
    String lastName = input.nextLine();
    input.close();
    System.out.println(name + " * " + nameList + " ** " + lastName);
}

控制台:

Enter a name:
aa
Enter a name list:
bb cc dd
Enter last name:
ee
aa * bb cc dd ** ee

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