编写程序以查找输入整数是负数还是零或正数。

问题描述

编写一个程序来查找输入整数是负数还是零或正数。



我尝试过：

write a program to find whether an input integer is negative or zero or positive.

What I have tried:

#include <stdio.h>
void main()
{
    int a = 0; // equal (=) added, Afzaal Ahmad Zeeshan
    printf("enter an integer\n");
    scanf("%d",&a);
    if(a>0)
    printf("the number is +ve");
    else if(a<o)
    printf("the number is negative");
    else
    printf("the number is zero");
}

推荐答案

#include <stdio.h>

void main() {
   int a,0;
   printf("enter an integer\n");
   scanf("%d",&a);
   if(a>0)
       printf("the number is +ve");
   else if(a<o)>
       printf("the number is negative");
   else
       printf("the number is zero");
}</stdio.h>

有很多问题，这会导致程序无法编译。我将逐一开始，首先，

There are many problems, and that would cause the program to not compile. I will start one by one, first of all,

int a = 0; 

是唯一可接受的表格。你不能写它， int a，0 。它不像 mov eax，0x0 的汇编指令。等等



最后， 0！= o 。在您自己的常规日使用中，您可以将0发音为O。但在一个程序中，它们有不同的含义。一个是整数值，另一个是变量的（可能）名称，否则是非法字符。因此，将其更改为，

Is the only acceptable form. You cannot write it like, int a, 0. It is not like assembly directives of, mov eax, 0x0. etc.

Finally, 0 != o. In your own regular day usage, you may pronounce "0" as, "O". But in a program, they have different meanings. One is an integer value, other is a (possible) name of a variable, otherwise illegal character. So, change that to,

else if(a<0)

然后编译它。如果编译器不将警告视为错误，那么它将起作用。

Then compile this. If compiler doesn't consider warnings as errors, then it would work.

#include <stdio.h>

int main() {
   int a = 0;
   printf("enter an integer\n");
   scanf("%d", &a);

   if(a > 0)  {
       printf("the number is +ve");
   } else if(a < 0) {
       printf("the number is negative");
   } else {
       printf("the number is zero");
   }
   return 0;
}
</stdio.h>

这样可行。此外，请记住编写具有良好可读性因素的正确代码。否则，读者实际上无法理解发生了什么。

This would work. Besides, remember to write proper code with a good readability factor. Otherwise, readers cannot actually understand what is going on.

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