通过 XSLT 用 XHTML 中的标签替换 style= 属性

问题描述

假设我在 XHTML 页面中有以下内容:

Say I have the following in an XHTML page:

<span style="color:#555555; font-style:italic">some text</span>

我将如何将其转换为:

<span style="color:#555555;"><em>some text</em></span>

推荐答案

这并不像看起来那么容易，因为 XSLT 不是字符串解析的最佳工具 - 但这正是您获取样式属性内容所需要的对一般.

This is not as easy as it seems since XSLT is not the best tool for string parsing - but that's exactly what you need to get the contents of the style attribute right generically.

但是，根据您输入的复杂程度，这样的内容可能就足够了(不过，我尝试尽可能通用):

However, depending on the complexity of your input, something like this might be enough (I tried to be as generic as possible, though):

<!-- it's a good idea to build most XSLT around the identity template -->
<xsl:template match="node()|@*">
  <xsl:copy>
    <xsl:apply-templates select="node()|@*" />
  </xsl:copy>
</xsl:template>

<!-- specific templates over general ones with complex if/choose inside -->
<xsl:template match="span[
  contains(translate(@style, ' ', ''), 'font-style:italic')
]">
  <xsl:copy>
    <xsl:copy-of select="@*" />
    <xsl:attribute name="style">
      <!-- this is pretty assumptious - might work, might break,
           depending on how complex the @style value is -->
      <xsl:value-of select="substring-before(@style, 'font-style')" />
      <xsl:value-of select="substring-after(@style, 'italic')" />
    </xsl:attribute>
    <em>
      <xsl:apply-templates select="node()" />
    </em>
  </xsl:copy>
</xsl:template>

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