如何从XML字符串获取JSON

问题描述

这是我的XML字符串:

This is my XML string:

<root>EXTRA
  <elem id="123" at="abc">HelloText</elem>
</root>

如何将其转换为JSON格式(带有属性和HelloText)?

How can I convert it to a JSON format (WITH attributes and HelloText) ?

推荐答案

因为RJS不想检查我向他建议的答案，所以它来自:

Because RJS doesn't want to check the answer i suggested to him, here is it from this post:

一个常见的陷阱是忘记json_encode()不尊重具有textvalue和attribute的元素.它将选择其中之一，即数据丢失.下面的功能解决了这个问题.如果决定使用json_encode/decode方式，建议使用以下功能.

A common pitfall is to forget that json_encode() does not respect elements with a textvalue and attribute(s). It will choose one of those, meaning dataloss. The function below solves that problem. If one decides to go for the json_encode/decode way, the following function is advised.

function json_prepare_xml( $domNode ){
  foreach( $domNode->childNodes as $node)
    if($node->hasChildNodes()) json_prepare_xml($node);
  if( $domNode->hasAttributes() && strlen($domNode->nodeValue) ){
    $domNode->setAttribute("nodeValue", $node->textContent );
    $node->nodeValue = "";
  }
  return $node;
}

$dom->loadXML( file_get_contents($xmlfile) );
json_prepare_xml($dom);
$sxml = simplexml_load_string( $dom->saveXML() );
$json = json_decode( json_encode( $sxml ) ) );

这样做，<foo bar="3">Lorem</foo>在您的JSON中将不会以{"foo":"Lorem"}结尾.

by doing so, <foo bar="3">Lorem</foo> will not end up as {"foo":"Lorem"} in your JSON.

这篇关于如何从XML字符串获取JSON的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！