问题描述
我有想要提取的数据.但是，由于第一列中有一些数据，因此我在第一列上遇到了麻烦，这使我很难使用awk解析它
I have this data that wanted to extract. However, im having trouble with the first column since some data has space in it making it hard for me to parse it using awk
6_MB06 SA003 1550 None uats admin 1270 1478640 1211360 none 2957656064 no 0 no 60021AA29H38028200000000000521D3 no no 0 no yes no no supported no no 18 2.60 193 no 0 Active optimized 0000 Not Available
6_VLS01 G 516 None uats admin 0 492880 176 none 1008291840 no 0 no 60021AA29H38028200000000000521D4 no no 0 no yes no no supported no no 99 2.20 0 no 0 Active optimized 0000 Not Available
6_VLS01 R 1550 None uats admin 1361 1478640 1297994 none 2957656064 no 0 no 60021AA29H38028200000000000521D5 no no 0 no yes no no supported no no 12 3.58 375 no 0 Active optimized 0000 Not Available
irexenvdi_np_cl1_2_001 10956 None ire_ct2_pool admin 8689 10449056 8286854 none 21396484375 no 0 no 60021AA29H38028200000000000521D6 no no 0 no yes no no supported no no 20 1.38 1050 no 0 Active optimized 0000 Not Available
irexenvdi_np_cl1_2_002 10956 None ire_ct2_pool admin 8696 10449056 8293878 none 21396484375 no 0 no 60021AA29H38028200000000000521D7 no no 0 no yes no no supported no no 20 1.36 1132 no 0 Active optimized 0000 Not Available
4_MA04-SA025 1550 None uats admin 1270 1478640 1211856 none 2957656064 no 0 no 60021AA29H38028200000000000630EC no no 0 no yes no no supported no no 18 1.92 316 no 0 Active optimized 0000 Not Available
4_G VLS01 516 None uats admin 7 492880 7264 none 1008291840 no 0 no 60021AA29H38028200000000000630ED no no 0 no yes no no supported no no 98 1.26 0 no 0 Active optimized 0000 Not Available
4_R VLS01 1550 None uats admin 1278 1478640 1218864 none 2957656064 no 0 no 60021AA29H38028200000000000630EE no no 0 no yes no no supported no no 17 2.19 423 no 0 Active optimized 0000 Not Available
尝试了此命令，我在另一个脚本中使用了此命令，因为输出在某种程度上相似，但未按预期工作.
Tried this command which i use in another script since output is somehow similar but it did not work as intended.
cat file | awk 'match($0, /[[:alnum:]]{32}/){ print $1, $2, substr($0, RSTART, RLENGTH)}' |column -t
运行会产生以下结果:
6_MB06 SA003 60021AA29H38028200000000000521D3
6_VLS01 G 60021AA29H38028200000000000521D4
6_VLS01 R 60021AA29H38028200000000000521D5
irexenvdi_np_cl1_2_001 10956 60021AA29H38028200000000000521D6
irexenvdi_np_cl1_2_002 10956 60021AA29H38028200000000000521D7
4_MA04-SA025 1550 60021AA29H38028200000000000630EC
4_G VLS01 60021AA29H38028200000000000630ED
4_R VLS01 60021AA29H38028200000000000630EE
但是想要这个:
6_MB06 SA003 1550 60021AA29H38028200000000000521D3
6_VLS01 G 516 60021AA29H38028200000000000521D4
6_VLS01 R 1550 60021AA29H38028200000000000521D5
irexenvdi_np_cl1_2_001 10956 60021AA29H38028200000000000521D6
irexenvdi_np_cl1_2_002 10956 60021AA29H38028200000000000521D7
4_MA04-SA025 1550 60021AA29H38028200000000000630EC
4_G VLS01 516 60021AA29H38028200000000000630ED
4_R VLS01 1550 60021AA29H38028200000000000630EE
推荐答案
如果您的第一个单词最多包含一个空格，则可以尝试
If your first word has at most one space in it, you can try
awk 'NF == 35 { print $1"@"$2, $3, $15} NF == 34 { print $1, $2, $14 }' file | column -t | sed 's/@/ /'
这会将第一个单词包含空格的行识别为具有额外的列(awk措辞中的字段)，将空格打印为@符号，然后使用column -t进行格式设置，然后将@替换为空格使用sed.
This recognizes rows with the first word containing a space as having an extra column (field in awk parlance), printing the space as a @ symbol, then formatting with column -t, then replacing the @ with a space using sed.
这篇关于使用awk将带有空格的第一列视为一列的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！