本文介绍了如何检测圆圈中的触摸的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我真的很帮助。我有点困惑。
i有一个圆形精灵,这个代码
I really assistance. Im a little confused.i have a circle sprite, and this code
-(void)ccTouchesBegan:(NSSet *)touches withEvent:(UIEvent *)event
{
CGSize winSize =[[CCDirector sharedDirector] winSize];
UITouch* myTouch = [touches anyObject];
CGPoint location = [myTouch locationInView: [myTouch view]];
location = [[CCDirector sharedDirector]convertToGL:location];
CCSprite *circleSprite = (CCSprite*)[self getChildByTag:30];
CGRect correctColorSprite1 = [circleSprite boundingBox];
if (CGRectContainsPoint(correctColorSprite1, location)) {
NSLog(@"inside");
}
因为我知道有一个边框
我已经读过一些论坛,我需要检测中心的精灵和触摸点的距离。但我真的不知道如何写的代码。我的圈子大小约为50分。
i have read in some forums that i need to detect distance of the centre of the sprite and the touch point. But i really don't know how to write that code. My circle size is around 50 points.
我希望有人可以帮助我给我一些改进的代码片段,以检测只在圆圈中的触摸。不与边界框。
I hope someone can help me out give me some snippets of a improved code to detect the touch only in the circle. Not with the bounding box. Your help is very great full.
推荐答案
请尝试以下操作:
-(void)ccTouchesBegan:(NSSet *)touches withEvent:(UIEvent *)event
{
CGSize winSize =[[CCDirector sharedDirector] winSize];
UITouch* myTouch = [touches anyObject];
CGPoint location = [myTouch locationInView: [myTouch view]];
location = [[CCDirector sharedDirector]convertToGL:location];
CCSprite *circleSprite = (CCSprite*)[self getChildByTag:30];
//CGRect correctColorSprite1 = [circleSprite boundingBox];
CGRect correctColorSprite1 = CGRectMake(
circleSprite.position.x - (circleSprite.contentSize.width/2),
circleSprite.position.y - (circleSprite.contentSize.height/2),
circleSprite.contentSize.width,
circleSprite.contentSize.height);
//find the center of the bounding box
CGPoint center=ccp(correctColorSprite1.size.width/2,correctColorSprite1.size.height/2);
//now test against the distance of the touchpoint from the center
if (ccpDistance(center, location)<50)
{
NSLog(@"inside");
}
}
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