本文介绍了调用类方法(使用构造函数)在php中没有对象实例化的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
Ive看了看,试过,但我找不到答案。
Ive looked and tried but I can't find an answer.
在PHP中,是否可以调用类的成员函数(当该类需要一个构造函数来接收参数时)而不将其实例化为一个对象?
In PHP, is it possible to call a class' member function (when that class requires a constructor to receive parameters) without instantiating it as an object?
代码示例(给出错误):
A code example (which gives errors):
<?php
class Test {
private $end="";
function __construct($value) {
$this->end=$value;
}
public function alert($value) {
echo $value." ".$this->end;
}
}
//this works:
$example=new Test("world");
$example->alert("hello");
//this does not work:
echo Test("world")::alert("hello");
?>
推荐答案
不幸的是PHP不支持这样做,但你是一个有创意的人:D
Unfortunately PHP doesn't have support to do this, but you are a creative and look guy :D
你可以使用工厂,样例:
You can use an "factory", sample:
<?php
class Foo
{
private $__aaa = null;
public function __construct($aaa)
{
$this->__aaa = $aaa;
}
public static function factory($aaa)
{
return new Foo($aaa);
}
public function doX()
{
return $this->__aaa * 2;
}
}
Foo::factory(10)->doX(); // outputs 20
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