解密错误：Pad块损坏

问题描述

我有以下代码。

    byte[] input = etInput.getText().toString().getBytes();
    byte[] keyBytes = new byte[] { 0x00, 0x01, 0x02, 0x03, 0x04, 0x05, 0x06, 0x07, 0x08, 0x09,
        0x0a, 0x0b, 0x0c, 0x0d, 0x0e, 0x0f, 0x10, 0x11, 0x12, 0x13, 0x14, 0x15, 0x16, 0x17 };

    SecretKeySpec key = new SecretKeySpec(keyBytes, "AES");

    Cipher cipher = Cipher.getInstance("AES/ECB/PKCS7Padding", "BC");

    // encryption pass
    cipher.init(Cipher.ENCRYPT_MODE, key);

    byte[] cipherText = new byte[cipher.getOutputSize(input.length)];
    int ctLength = cipher.update(input, 0, input.length, cipherText, 0);
    ctLength += cipher.doFinal(cipherText, ctLength);

    cipher.init(Cipher.DECRYPT_MODE, key);
    byte[] plainText = new byte[cipher.getOutputSize(ctLength)];
    int ptLength = cipher.update(cipherText, 0, ctLength, plainText, 0);

    String strLength = new String(cipherText,"US-ASCII");
    byte[] byteCiphterText = strLength.getBytes("US-ASCII");
    Log.e("Decrypt", Integer.toString(byteCiphterText.length));

    etOutput.setText(new String(cipherText,"US-ASCII"));

    cipherText  = etOutput.getText().toString().getBytes("US-ASCII");
    Log.e("Decrypt", Integer.toString(cipherText.length));

    ptLength += cipher.doFinal(plainText, ptLength);
    Log.e("Decrypt", new String(plainText));
    Log.e("Decrypt", Integer.toString(ptLength));

完美无缺。
但是一旦我将它转换为课程。它总是在这一行中出现错误。

It works perfectly.But once I convert it to the class. It always hit the error in this line.

 ptLength += cipher.doFinal(plainText, ptLength);

 Error:Pad block corrupted

我已经检查过，两个代码都是完全正确的相同。即使转换字符串中传递给字节的值也与上面的代码没有什么不同。知道代码有什么问题吗？

I have checked and both code are exactly the same. Even the value passed in conversion string to byte all is no different from the code above. Any idea what's wrong with the code?

public String Encrypt(String strPlainText) throws Exception, NoSuchProviderException,
        NoSuchPaddingException {
    byte[] input = strPlainText.getBytes();
    byte[] keyBytes = new byte[] { 0x00, 0x01, 0x02, 0x03, 0x04, 0x05,
            0x06, 0x07, 0x08, 0x09, 0x0a, 0x0b, 0x0c, 0x0d, 0x0e, 0x0f,
            0x10, 0x11, 0x12, 0x13, 0x14, 0x15, 0x16, 0x17 };

    SecretKeySpec key = new SecretKeySpec(keyBytes, "AES");

    Cipher cipher = Cipher.getInstance("AES/ECB/PKCS7Padding", "BC");

    // encryption pass
    cipher.init(Cipher.ENCRYPT_MODE, key);

    byte[] cipherText = new byte[cipher.getOutputSize(input.length)];
    int ctLength = cipher.update(input, 0, input.length, cipherText, 0);
    ctLength += cipher.doFinal(cipherText, ctLength);

    return new String(cipherText, "US-ASCII");
}

public String Decrypt(String strCipherText) throws Exception,
        NoSuchProviderException, NoSuchPaddingException {
    byte[] cipherText = strCipherText.getBytes("US-ASCII");
    int ctLength = cipherText.length;
    byte[] keyBytes = new byte[] { 0x00, 0x01, 0x02, 0x03, 0x04, 0x05,
            0x06, 0x07, 0x08, 0x09, 0x0a, 0x0b, 0x0c, 0x0d, 0x0e, 0x0f,
            0x10, 0x11, 0x12, 0x13, 0x14, 0x15, 0x16, 0x17 };

    SecretKeySpec key = new SecretKeySpec(keyBytes, "AES");

    Cipher cipher = Cipher.getInstance("AES/ECB/PKCS7Padding", "BC");

    // decryption pass
    cipher.init(Cipher.DECRYPT_MODE, key);
    byte[] plainText = new byte[cipher.getOutputSize(ctLength)];
    int ptLength = cipher.update(cipherText, 0, ctLength, plainText, 0);
    ptLength += cipher.doFinal(plainText, ptLength);

    return new String(plainText);
}

推荐答案

正如Yann Ramin所说，使用字符串是密码输入/输出失败。这是二进制数据

As Yann Ramin said, using String is a failure for cipher in/output. This is binary data that

• 可以包含0x00


• 可以包含未定义或映射的值使用的编码中的奇怪位置

使用第一个示例中的plain byte []或者使用十六进制编码或base64编码字节[]。

Use plain byte[] as in your first example or go for hex encoding or base64 encoding the byte[].

// this is a quick example - dont use sun.misc inproduction
//  - go for some open source implementation
String encryptedString = new sun.misc.BASE64Encoder.encodeBuffer(encryptedBytes);

这个字符串可以安全地传输并映射回字节。

This string can be safely transported and mapped back to bytes.

编辑

处理长度问题最安全的方法是始终使用流媒体实现（恕我直言）：

Perhaps safest way to deal with the length issue is to always use streaming implementation (IMHO):

示例

static public byte[] decrypt(Cipher cipher, SecretKey key, byte[]... bytes)
        throws GeneralSecurityException, IOException {
    cipher.init(Cipher.DECRYPT_MODE, key);
    ByteArrayOutputStream bos = new ByteArrayOutputStream();
    for (int i = 0; i < bytes.length; i++) {
        bos.write(cipher.update(bytes[i]));
    }
    bos.write(cipher.doFinal());
    return bos.toByteArray();
}

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