问题描述
与冰淇淋三明治设备可以使用屏幕上的软按键,这意味着一些屏幕房地产的采取的是这些密钥。我需要真正的屏幕分辨率,而不是决议减去软键所占用的空间。
我已经试过以下,但既不作品:
显示显示= getWindowManager()getDefaultDisplay()。
INT宽度= display.getWidth();
INT高= display.getHeight();
Log.d(SCREEN RES,宽:+宽+:+高的高度。);
DisplayMetrics指标=新DisplayMetrics();
。getWindowManager()getDefaultDisplay()getMetrics(度量)。
身高= metrics.heightPixels;
宽度= metrics.widthPixels;
Log.d(SCREEN RES,宽:+宽+:+高的高度。);
下面是输出:
12-19 20:18:42.012:D /屏幕RES(20752):宽:1196高:720
12-19 20:18:42.012:D /屏幕RES(20752):宽:1196高:720
真正的屏幕分辨率为1280×720像素,而不是1196×720像素。
任何想法?
修改
我用下面的code,使应用程序全屏:
。 getWindow()getDecorView()setSystemUiVisibility(View.SYSTEM_UI_FLAG_HIDE_NAVIGATION);
该API返回像素的应用程序可以使用的数量,所以这是正确的结果。
Devices with Ice Cream Sandwich can use on-screen soft keys, and this means that some of the screen estate is taken by these keys. I need to get the real screen resolution, and not the resolution minus the space taken up by the soft keys.
I've tried the following, but neither works:
Display display = getWindowManager().getDefaultDisplay();
int width = display.getWidth();
int height = display.getHeight();
Log.d("SCREEN RES", "Width: " + width + ". Height: " + height);
DisplayMetrics metrics = new DisplayMetrics();
getWindowManager().getDefaultDisplay().getMetrics(metrics);
height = metrics.heightPixels;
width = metrics.widthPixels;
Log.d("SCREEN RES", "Width: " + width + ". Height: " + height);
Here's the output:
12-19 20:18:42.012: D/SCREEN RES(20752): Width: 1196. Height: 720
12-19 20:18:42.012: D/SCREEN RES(20752): Width: 1196. Height: 720
The real screen resolution is 1280 x 720 pixels, not 1196 x 720 pixels.
Any ideas?
Edit
I'm using the following code to make the app full screen:
getWindow().getDecorView().setSystemUiVisibility(View.SYSTEM_UI_FLAG_HIDE_NAVIGATION);
The API returns the number of pixels an app can use, so this is the correct result.
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