本文介绍了打印出数组列表中的所有对象的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我需要能够打印出数组列表中的 Student 对象(所有变量).这可能吗?当我尝试打印它时会输出此类内容,例如 student.Student@82701e
.我认为它是十六进制
或其他东西
I need to be able to print out the Student objects(all variables) in my array list. Is this possible? When i try to print it outputs this sort of thing e.g student.Student@82701e
. I think it's hexadecimal
or something
这是我的代码:
package student;
public class Student {
private String studentName;
private String studentNo;
private String email;
private int year;
public Student() {
this.studentName = null;
this.studentNo = null;
this.email = null;
this.year = -1;
}
public Student(String nName, String nNum, String nEmail, int nYr) {
this.studentName = nName;
this.studentNo = nNum;
this.email = nEmail;
this.year = nYr;
}
public void setStudentName(String newStudentName) {
this.studentName = newStudentName;
}
public void setStudentNo(String newStudentNo) {
this.studentNo = newStudentNo;
}
public void setEmail(String newEmail) {
this.email = newEmail;
}
public void setYear(int newYear) {
this.year = newYear;
}
public String getStudentName() {
return studentName;
}
public String getStudentNo() {
return studentNo;
}
public String getEmail() {
return email;
}
public int getYear() {
return year;
}
}
package student;
import java.util.ArrayList;
import java.util.List;
import java.util.Scanner;
public class studentTest {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
List<Student> Students = new ArrayList();
Student student1 = new Student();
student1.setStudentName("Bob Marley");
student1.setStudentNo("N0002");
student1.setEmail("student2@student.com");
student1.setYear(2);
Students.add(student1);
Student student2 = new Student();
student2.setStudentName("Bill Harvey");
student2.setStudentNo("N0003");
student2.setEmail("student3@student.com");
student2.setYear(2);
Students.add(student2);
Student student3 = new Student();
student3.setStudentName("John Beans");
student3.setStudentNo("N0004");
student3.setEmail("student4@student.com");
student3.setYear(2);
Students.add(student3);
System.out.println("Add new students: ");
System.out.println("Enter number of students to add: ");
int countStudents = input.nextInt();
for (int i = 0; i < countStudents; i++) {
Student newStudents = new Student();
System.out.println("Enter details for student: " + (i + 1));
System.out.println("Enter name: ");
newStudents.setStudentName(input.next());
System.out.println("Enter Number: ");
newStudents.setStudentNo(input.next());System.out.println("Search by student number: ");
System.out.println("Enter email: ");
newStudents.setEmail(input.next());
System.out.println("Enter year: ");
newStudents.setYear(input.nextInt());
Students.add(newStudents);
}
}
}
推荐答案
重写 Student
类中的 toString()
方法如下:
Override toString()
method in Student
class as below:
@Override
public String toString() {
return ("StudentName:"+this.getStudentName()+
" Student No: "+ this.getStudentNo() +
" Email: "+ this.getEmail() +
" Year : " + this.getYear());
}
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