问题描述
我是Jquery的新手。我有一个项目,有复选框,如果他们的状态改变,那么我更新一些sql表。
但我决定首先从简单的事情开始学习如何工作...
所以,我想传递给Jquery函数,如果复选框状态发生变化,则为php变量。
我有这样的代码:
<?php?>
< HTML>
< HEAD>
< TITLE>新文档< / TITLE>
< META NAME =AuthorCONTENT =>
< META NAME =关键字CONTENT =>
< META NAME =说明CONTENT =>
< script type =text / javascriptsrc =jquery-1.4.2.js>< / script>
< script type =text / javascript>
function my_function(var mensagem_id)
{
alert(Sucesso,Mensagemnº:+ mensagem_id);
}
< / script>
< / HEAD>
< BODY>
<?php
$ mensagem_id =3;
echo $ mensagem_id;
?>
< input type ='checkbox'name ='lida'value ='mensagem_id'onchange ='my_function($ mensagem_id)'/>
< / BODY>
< / HTML>
但是在萤火虫中,我一直得到讯息(function my_function()未定义) p>
任何人都可以帮助我吗?
函数定义,使用<?php echo
和?>>
围绕 $ mensagem_id
在 onchange
调用。
但是你根本没有使用jQuery,只是简单的Javascript。
I'm new to Jquery. I have a project that has checkboxes and if their status change, then I update some sql table.
But i decided to start with the simple things first to learn how this works...
So, I want to pass to a Jquery function, a php variable if a checkbox status changes.
I have this code:
<?php ?>
<HTML>
<HEAD>
<TITLE> New Document </TITLE>
<META NAME="Author" CONTENT="">
<META NAME="Keywords" CONTENT="">
<META NAME="Description" CONTENT="">
<script type="text/javascript" src="jquery-1.4.2.js"></script>
<script type="text/javascript">
function my_function(var mensagem_id)
{
alert("Sucesso, Mensagem nº: " + mensagem_id);
}
</script>
</HEAD>
<BODY>
<?php
$mensagem_id = "3";
echo $mensagem_id;
?>
<input type='checkbox' name='lida' value='mensagem_id' onchange='my_function($mensagem_id)'/>
</BODY>
</HTML>
But in firebug I keep getting the message (function my_function() not defined)...
Can anyone help me?
Take "var" away from the function definition, and use <?php echo
and ?>
around $mensagem_id
in the onchange
call.
But you're not using jQuery at all, just simple Javascript.
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