新孩子的xml缩进和换行符

问题描述

我有一个如下所示的xml文件.

I have a xml file that looks like a following.

<root>
    <children>
        <foo1 val="23"/>
        <foo2 val="14"/>
    </children>
</root>

我希望使用功能 xmlNewChild()后跟 xmlNewProp()将名称为 foo 的新子代添加到节点.我想生成类似以下的内容.

I wish to add a new child with name foo to the node using the functions xmlNewChild() followed by xmlNewProp(). I would like to generate something like the following.

<root>
    <children>
        <foo1 val="23"/>
        <foo2 val="14"/>
        <foo3 val="5"/>
    </children>
</root>

但是，我总是得出以下结论.

However, I always end up with the following.

<root>
    <children>
        <foo1 val="23"/>
        <foo2 val="14"/>
    <foo3 val="5"/></children>
</root>

我确实知道libxml2默认情况下不支持空格.但是，有没有一种方法可以达到我想要的结果?对于新添加的孩子，我需要将这些标签放在开头，最后将换行符放在上面.

I do understand that libxml2 does not favor white spaces by default. However, is there a way to achieve the result I want? I need to get those tabs in front and newlines in the end for the newly added child.

任何帮助将不胜感激.谢谢！

Any help would be appreciated. Thanks!

推荐答案

问题是XML结构实际上看起来像这样:

The issue is that the XML structure actually looks like this:

<root>
    [TEXT:"\n    "]
    <children>
        [TEXT:"\n        "]
        <foo1 val="23"/>
        [TEXT:"\n        "]
        <foo2 val="14"/>
        [TEXT:"\n    "]
    </children>
    [TEXT:"\n"]
</root>

如果仅在children的末尾添加一个额外的元素节点，则可以看到所得到的结果是不可避免的(因为没有文本节点可以承载换行符，并且foo3和).

If you just add an extra element node at the end of children, you can see that what you get is inevitable (as there is no text node to carry a newline and the desired indentation between foo3 and children).

您需要编辑children中的最后一个文本节点(紧接在foo2之后的文本节点)以为其提供额外的缩进，然后附加新节点，然后将新文本节点附加到缩进</children>中.或者，您可以在children中插入与先前的文本节点相同的文本节点，然后在children中的最终文本节点之前插入新的元素节点.两者都应该给您相同的结果，一个您需要的结果:

You need to edit the final text node inside children (the one immediately after foo2) to give it an extra indent, then append your new node, then append a new text node to indent </children>. Alternately, you can insert a text node identical to previous text nodes inside children and then your new element node just before the final text node in children. Both should give you the same result, the one you need:

<root>
    [TEXT:"\n    "]
    <children>
        [TEXT:"\n        "]
        <foo1 val="23"/>
        [TEXT:"\n        "]
        <foo2 val="14"/>
        [TEXT:"\n        "]
        <foo3 val="5"/>
        [TEXT:"\n    "]
    </children>
    [TEXT:"\n"]
</root>

另一种方法是让libxml2为您自动缩进输出.这将破坏现有的缩进并从头开始重做. 此处是一个相关的答案.

Another approach is to have libxml2 autoindent the output for you. This will destroy existing indentation and redo it from scratch. Here is a relevant answer.

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