用 PHP 编写归并排序

问题描述

我尝试在 PHP 中编写一个涉及小数组的基本合并排序，但问题是执行大约需要一分钟左右，然后返回:

致命错误:允许的内存大小为 536870912 字节已用尽(已尝试在第 39 行的/Users/web/www/merge.php 中分配 35 个字节

有谁知道代码可能出错的地方(如果有的话)?我已经盯着这个看了一个小时.

 0 || count(right) > 0){if(count($left) > 0 && count(right) > 0){if($left[0] <= $right[0]){$result[] = array_shift($left);} 别的 {$result[] = array_shift($right);}} elseif (count($left) > 0){$result[] = array_shift($left);} elseif (count($right) > 0){$result[] = array_shift($right);}}打印数组($result)；退出；返回 $result;}函数print_array($array){echo "
";print_r($array);echo "<br/>";echo "</pre>";}?>
 解决方案 
在你的 merge 函数中，你调用 count on right 而不是 $right.PHP 假定这是一个字符串常量(至少在 5.3.9 中)并且当被转换为一个始终只有一个元素的数组时.所以 count(right) 总是一个，你永远不会退出第一次合并.
I have tried to write a basic merge sort in PHP involving a small array, yet the problem is it takes about a minute or so to execute, and returns:
Does anyone have an idea where the code might be going wrong (if at all)? I've been staring at this for a good hour now.
<?php

$array = array(8,1,2,5,6,7);
print_array($array);
merge_sort($array);
print_array($array);

function merge_sort(&$list){
    if( count($list) <= 1 ){
        return $list;
    }

    $left =  array();
    $right = array();

    $middle = (int) ( count($list)/2 );

    // Make left
    for( $i=0; $i < $middle; $i++ ){
        $left[] = $list[$i];
    }

    // Make right
    for( $i = $middle; $i < count($list); $i++ ){
        $right[] = $list[$i];
    }

    // Merge sort left & right
    merge_sort($left);
    merge_sort($right);

    // Merge left & right
    return merge($left, $right);
}

function merge(&$left, &$right){
    $result = array();

    while(count($left) > 0 || count(right) > 0){
        if(count($left) > 0 && count(right) > 0){
            if($left[0] <= $right[0]){
                $result[] = array_shift($left);
            } else {
                $result[] = array_shift($right);
            }
        } elseif (count($left) > 0){
            $result[] = array_shift($left);
        } elseif (count($right) > 0){
            $result[] = array_shift($right);
        }
    }

    print_array($result);exit;

    return $result;
}

function print_array($array){
    echo "<pre>";
    print_r($array);
    echo "<br/>";
    echo "</pre>";
}

?>
 解决方案 
In your merge function, you call count on right instead of $right. PHP assumes this is a string constant (at least in 5.3.9) and when casted into an array that always has one element. So count(right) is always one, and you never exit the first merge.
                        
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