问题描述
我正在头文件中定义一个结构,然后在相应的.cpp文件中设置其成员。为此,我使用的功能是在其作用域内创建(相同)结构,然后返回它。像这样的东西:
I am defining a structure in a header file, and then setting its members in the corrosponding .cpp file. For doing this I am using a function that is supposed to create a (same) structure in its scope, and then return it. Something like this:
标题中:
#include <things>
class GLWindow : public QGLWidget, public QGLFunctions
{
Q_OBJECT
public:
GLWindow(QWidget *parent = 0);
~GLWindow();
//....
struct Drawable
{
GLuint vertexBuffer;
GLuint indexBuffer;
int faceCount;
QMatrix4x4 transform;
}cube;
GLuint cubeTex;
Drawable CreateDrawable(GLfloat* C_vertices, GLfloat* C_tex, GLfloat* C_normals, GLushort* C_facedata, int faces);
//.....
};
在cpp文件中:
#include "glwindow.h"
Drawable GLWindow :: CreateDrawable(GLfloat *C_vertices, GLfloat *C_tex, GLfloat *C_normals, GLushort *C_facedata, int faces)
{
int faceCount =faces;
QMatrix4x4 Transform;
Transform.setToIdentity();
GLuint VB;
/*Create vertexbuffer...*/
GLuint IB;
/*Create indexbuffer...*/
Drawable drawable;
drawable.faceCount = fCount;
drawable.transform = Transform;
drawable.vertexBuffer = VB;
drawable.indexBuffer = IB;
return drawable;
}
void GLWindow :: someOtherFunction()
{
//.....
cube = CreateDrawable(cube_vertices, cube_tex, cube_normals, cube_facedata, cube_face);
//.....
}
我遇到了错误指出'Drawable'没有命名类型,但是我无法理解为什么会收到此错误,或者我可以采取什么措施来消除此错误。
I am getting an error stating that 'Drawable' does not name a type, but I can't comprehend why I am getting this error, or what I can do to eliminate it.
推荐答案
您需要在cpp文件中限定 Drawable
:
You need to qualify Drawable
in the cpp file:
GLWindow::Drawable GLWindow :: CreateDrawable(GLfloat *C_vertices, GLfloat *C_tex, GLfloat *C_normals, GLushort *C_facedata, int faces)
在cpp文件中,在成员方法之外,您正在类上下文之外进行操作。在方法内部,可以使用 Drawable
,但在外部(包括返回类型),则需要使用 GLWindow :: Drawable
。
In the cpp file, outside the member methods, you're operating outside the class context. Inside the methods you can use Drawable
, but outside (including return type), you need to use GLWindow::Drawable
.
那是如果您实际上是从方法中返回 Drawable
而不是无效
-也是一个错误。
That's if you're actually returning a Drawable
from the method, not a void
- also an error.
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