本文介绍了scanf函数不会要求输入第二次的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
#include "stdio.h"
int main(void)
{
int order, nextp, N=3;
char cont;
nextp = 0;
printf("\nShould we continue (y or n): ");
scanf("%c", &cont);
if (cont != 'y') return;
for(; nextp < N; nextp++)
{
printf("Enter order number: ");
scanf("%d", &order);
printf("you have entered %d\n", order);
printf("okay now continue with cont\n");
printf("enter cont y or n: ");
scanf("%c", &cont);
if (cont != 'y')
{
printf("\nnot equal to y\n");
break;
}
printf("after intepreting t[0]");
}
return 0;
}
输出看起来像这样
The output looks like this
Should we continue (y or n): y
Enter order number: 45
you have entered 45
okay now continue with cont
enter cont y or n:
not equal to y
第二个输入被跳过。为什么呢?
The second input was skipped. Why?
推荐答案
,这种情况正在发生。
用
because of newline character already in stdin , this is happening.use
scanf(" %c", &cont);
而不是
scanf("%c", &cont);
请注意%C前一个空格。
note one space before %c.
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