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问题描述
我正在使用此解决方案来尝试消除我的问题,但是却失败了:
I am following this solution to try and eliminate my issue, but am failing miserably: RESTEasy: Could not find writer for content-type application/json type
这是我的Maven依赖项:
Here are my maven dependencies:
<dependency>
<groupId>org.jboss.resteasy</groupId>
<artifactId>resteasy-jaxrs</artifactId>
<version>2.2.1.GA</version>
</dependency>
<dependency>
<groupId>org.codehaus.jackson</groupId>
<artifactId>jackson-mapper-asl</artifactId>
<version>1.9.9</version>
</dependency>
<dependency>
<groupId>javax.xml.bind</groupId>
<artifactId>jaxb-api</artifactId>
<version>2.2.12</version>
</dependency>
这是我创建的XML类,可以进行编组/拆组.
Here is a XML class that I created that I marshall/unmarshall.
@XmlAccessorType(XmlAccessType.FIELD)
@XmlRootElement(name = "Cools")
public class CoolXml {
@XmlAttribute
private Boolean isCool;
public Boolean getIsCool() {
return isCool;
}
public void setIsCool(final Boolean isCool) {
this.isCool = isCool;
}
}
使用此代码调用端点时,最后一行会生成错误:
When calling the endpoint with this code, the last line generates the error:
final String url = "http://localhost:8080/sample/getcools";
final ClientRequest request = new ClientRequest(url);
request.header(HttpHeaderNames.ACCEPT, MediaType.APPLICATION_XML);
final CoolXml req = new CoolXml(project);
request.body("application/xml", req);
final ClientResponse<CoolXmlResponse> response = request.post(CoolXmlResponse.class);
我收到超级烦人的错误:
I get the super annoying error:
java.lang.RuntimeException: could not find writer for content-type application/xml type: cool.CoolXml
我需要任何其他依赖吗?
Do I need any additional dependencies?
推荐答案
我最终使用了这种依赖关系:
I ended up using this dependency:
<dependency>
<groupId>com.sun.jersey</groupId>
<artifactId>jersey-client</artifactId>
<version>1.8</version>
</dependency>
然后,我最终使用以下类来测试请求:
Then, I ended up using the following classes to test a request:
final Client client = Client.create();
final WebResource webResource = client.resource(url);
final CoolXml requestXml = new CoolXml();
... some data setting
final ClientResponse response = webResource.accept("application/xml").post(ClientResponse.class, requestXml);
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