问题描述
我是UI开发的新手，所以如果这不是棱角的话，请原谅我.我在这里使用Angular 8和打字稿.无论如何，我创建了一个弹出模式，我不想在我的整个网站上使用它.看起来不错，但是当我将其插入这样的组件中
I'm new to UI development so forgive me if this isn't angular. I'm using Angular 8 and typescript here. Anyways I created a pop-up modal that I wan't to use throughout my website. It looks great but when I plug it into my components like this
从'src/app/modals/pop-up-modal/pop-up-options-interface'导入{IPopUpOptions，IPopUpButton};
我的SonarQube CI/CD管道说:要么删除此导入，要么将其添加为依赖项.应在package.json文件中明确列出依赖项.导入未声明为依赖项的模块使其成为隐式的，并且必然会造成问题."这是什么意思?如何正确使用弹出窗口，使其遵守此规则?
My SonarQube CI/CD pipeline says "Either remove this import or add it as a dependency. Dependencies should be explicitly listed in the package.json file. Importing a module that is not declared as a dependency makes it an implicit one and is bound to create problems." What does this mean? How can I use my pop-up properly so that it abides by this rule?
推荐答案
尝试将'./'添加到您的导入路径:'./src/app/modals/pop-...'.否则，它可能被视为依赖项导入(即从node_modules导入)，而不是文件系统导入.
Try adding './' to your import path: './src/app/modals/pop-...'. Without that, it might be seen as a dependency import (i.e., from node_modules) rather than a file system import.
这篇关于角度代码闻到“要么删除此导入，要么将其添加为依赖项".当使用我写的接口时.如何使我的代码合规?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！