问题描述
我正在尝试将列表从cpp传递给python并将其取回.最初,我尝试传递一个值并获取一个值.有效.现在,我试图传递完整的数组/列表,下面是我的cpp代码:
I am trying to pass a list to python from cpp and taking it back. Initially I tried to pass a single value and get back one value. It worked. Now I am trying to pass the complete array/list Below is my cpp code:
#include <iostream>
#include <Python.h>
#include <numpy/arrayobject.h>
#include <typeinfo>
using namespace std;
int main()
{
Py_Initialize();
PyObject *sys = PyImport_ImportModule("sys");
PyObject *path = PyObject_GetAttrString(sys, "path");
PyList_Append(path, PyString_FromString("."));
PyObject *pName, *pModule, *pDict, *pFunc, *pArgs, *pValue;
// Build the name object
pName = PyString_FromString("mytest");
// Load the module object
pModule = PyImport_Import(pName);
// pDict is a borrowed reference
pDict = PyModule_GetDict(pModule);
// pFunc is also a borrowed reference
pFunc = PyObject_GetAttrString(pModule, "stuff");
if (!PyCallable_Check(pFunc))
PyErr_Print();
PyObject *list = PyList_New (5);
Py_ssize_t size = PyList_GET_SIZE(list);
for(Py_ssize_t s = 0; s < size; s++ )
{
PyList_SetItem(list, s, Py_BuildValue("d", 2.5));
}
PyObject* result = PyObject_CallObject(pFunc, list);
if(result==NULL)
{cout << "FAILED ..!!" << endl;}
cout << result << endl;;
return 0;
}
我总是收到失败.. !!".
I am always getting "FAILED..!!".
这是我的mytest.py
Here is my mytest.py
def stuff(a):
x=a
return x
有什么建议可以解决我的问题吗?
Any suggestions where I might be going wrong?
推荐答案
来自文档:
PyObject_CallFunctionObjArgs
记录为:
因此将您的呼叫更改为以下内容:
So change your call to the following:
PyObject* result = PyObject_CallFunctionObjArgs(pFunc, list, NULL);
(或者您可以将列表包装在另一个列表中,然后继续使用CallObject
,但这到目前为止是更简单的解决方案)
(or you could wrap your list inside another list and keep on using CallObject
, but this is by far the easier solution)
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