问题描述
我正在尝试在 python 中实现一个矩形脉冲序列.
I'm trying to implement a rectangular pulse train in python.
我搜索了scipy,没有实现的信号.http://docs.scipy.org/doc/scipy/reference/signal.html
I searched scipy and there is no signal that implements.http://docs.scipy.org/doc/scipy/reference/signal.html
在matlab中有一个名为pulstran的信号:http://es.mathworks.com/help/signal/ref/pulstran.html
In matlab there is a signal named pulstran:http://es.mathworks.com/help/signal/ref/pulstran.html
matlab 中的代码示例如下:
An example of code in matlab would be like this:
T=10; %Period
D=5; %Duration
N=10; %Number of pulses
x=linspace(0,T*N,10000);
d=[0:T:T*N];
y=pulstran(x,d,'rectpuls',D);
plot(x,y);
ylim([-1,2]);
我如何在 python 中实现这个信号?
How i could implement this signal in python?
谢谢.
推荐答案
如果您只是在寻找周期性脉冲序列,就像您给出的示例一样 - 这是一个打开 5 个周期然后关闭 5 个周期的脉冲序列:
If you're looking for just periodic pulse trains, like the example you gave - here's a pulse train that is on for 5 cycles then off for five cycles:
N = 100 # sample count
P = 10 # period
D = 5 # width of pulse
sig = np.arange(N) % P < D
给予
plot(sig)
您可以在此处将 np.arange(N)
替换为您的 linspace
.请注意,这与您的代码等效,因为脉冲未居中.
You can replace np.arange(N)
with your linspace
here. Note this is not equivalent to your code, as the pulses are not centered.
这是一个完全可配置的脉冲序列:
And here's a fully configurable pulse train:
def rect(T):
"""create a centered rectangular pulse of width $T"""
return lambda t: (-T/2 <= t) & (t < T/2)
def pulse_train(t, at, shape):
"""create a train of pulses over $t at times $at and shape $shape"""
return np.sum(shape(t - at[:,np.newaxis]), axis=0)
sig = pulse_train(
t=np.arange(100), # time domain
at=np.array([0, 10, 40, 80]), # times of pulses
shape=rect(10) # shape of pulse
)
给予:
我认为这是 matlab 的 pulsetran
函数比 Python 中的单行实现更令人困惑的情况之一,这可能是 scipy 不提供它的原因.
I think this is one of those cases where matlab's pulsetran
function is more confusing than the one-line implementation of it in python, which is possibly why scipy does not provide it.
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