二维数组和指针

问题描述

我有以下的code片断：

I have the following code snippet:

char board[3][3] = {
                     {'1','2','3'},
                     {'4','5','6'},
                     {'7','8','9'}
                   };

printf("address of board : %p\n", &board);
printf("address of board[0] : %p\n", &board[0]);

两者的printf（）语句都打印相同的值： 0x0013ff67

Both printf() statements all print the same value: 0x0013ff67

1. 按我的知识，板（即）数组名重新presents第一子阵（即）板[0] 和地址

板[0] 重新presents第一要素的第一阵列中的地址（即）板[0] [0]

board[0] represents the address of first element in the first array (i.e) board[0][0]

为什么会出现在我所有的的printf（）语句相同的地址？我希望不同的地址，这两个语句。

Why am I getting the same address in all my printf() statements? I expect different addresses for both statements.

我是pretty新的这个东西，不理解这种行为。请赐教。

I am pretty new to this stuff and don't understand this behavior. Kindly enlighten me.

推荐答案

尽管这是一个二维数组，内存里面将重新psented为线性阵列$ P $。所以当你说，板[0] [0]它仍然指向线性阵列中的第一个元素，因此相同的内存地址。

Though it's a 2D array, inside the memory it will be represented as linear array. so when you say, board[0][0] it still points to the first element in that linear array and hence the same memory address.

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